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makkiz [27]
3 years ago
9

2(x-3)-12 = -4 How do I solve this equations

Mathematics
1 answer:
deff fn [24]3 years ago
3 0

Answer:

x= 7

Step-by-step explanation:

1st step: Multiply the factor (outside number) with the numbers and variable(s) in the box. This results in 2(x-3) = 2x-6

2nd Step: continue the rest of the equation since there are no more brackets left so 2x-6-12=-4

3rd Step: send -12 to the other side of the equation (side changes sign changes) so it will become 2x-6=-4+12    (You are actually supposed to make the variable alone on one side of the equation so that you would be able to calculate its value)

4th step: 2x-6=8 ---> send -6 to the other side as well which will then result in 2x=14

5th step: since 2 is being multiplied by x, when you send it to the other side (to make x alone) you will divide 14 by 2 ( sign of 2 changes from multiplication to division)

Final Step: x=7

You might be interested in
Please help! will mark brainliest
marin [14]

The correct answer is D.

x= -4 and y=2

left 4  up 2


7 0
3 years ago
when 6 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.
sveta [45]

When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1

<h3><u>Solution:</u></h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = a^2

6 is subtracted from the square of a number = a^2 - 6

5 times the number = 5 \times a

<em><u>So we can frame a equation as:</u></em>

6 is subtracted from the square of a number = 5 times the number

a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0

<em><u>Let us solve the above quadratic equation</u></em>

For a quadratic equation ax^2 + bx + c = 0 where a \neq 0

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here in this problem,

a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6

Substituting the values in above quadratic formula, we get

\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}

We have two solutions for "a"

\begin{array}{l}{a=\frac{5+7}{2} \text { and } a=\frac{5-7}{2}} \\\\ {a=\frac{12}{2} \text { and } a=\frac{-2}{2}}\end{array}

<h3>a = 6 or a = -1</h3>

We have asked negative solution. So a = -1

Thus the negative solution is -1

6 0
3 years ago
The sales tax in Mansfield is 8.25% on anything purchased. What is the percent of the original price you will pay? Write your an
Fynjy0 [20]
If the tax was 10%, then you’d end up paying the original 100% plus the additional 10% tax, so you’d pay 110% of the original price.

In your example, it’s the same, except you have 8.25% tax, so you’d pay 100%+8,25% or 108.25% of the original price.
That’s stated as a percent.

To convert a percent to a decimal, you divide by 100:
108.25 ÷ 100 = 1.0825

To convert a decimal to a fraction, you have to know the place value of the smallest place. In this case, the 5 is in the ten thousandths place.
10825/10000

You can always double check that fraction on a calculator.
7 0
3 years ago
GUYS PLZ HELP ME!!!!!!
siniylev [52]

Answer:

B E F G

Step-by-step explanation:

Polygons are 2 dimensional shapes with straight edges (no curved edges). The shape needs to be closed up entirely to be a polygon. It cannot have any intersecting line segments

A can't be a polygon because the shape isn't closed up entirely

C can't be a polygon because it is a 3d shape

D can't be a polygon because it has curved edges.

H can't be a polygon because it isn't closed up (there are no line segments).

I can't be a polygon because polygons cannot have intersecting lines

J can't be a polygon because polygons cannot have intersecting lines

I hope this helps! If it does, a rate or brainliest would be much appreciated. :)

7 0
3 years ago
Simplify the Expression
nlexa [21]

Answer:

125a^{3}b^{2}

Step-by-step explanation:

6 0
3 years ago
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