answer:
10315
I used a calculator
step by step
(- 4305) - |(-2508) + (- 3502)|
Rewrite
Remove the parentheses
4305 - |
Calculate
4305 - |
- 2508 - 3502
- 6010
Calculate the absolute value
- 4305 - 6010
Calculate
Solution
- 10315
Number of child tickets bought is 20
<h3><u>
Solution:</u></h3>
Given that It cost 5 dollars for a child ticket and 8 dollars for a adult ticket
cost of each child ticket = 5 dollars
cost of each adult ticket = 8 dollars
Let "c" be the number of child tickets bought
Let "a" be the number of adult tickets bought
Total tickets sold were 110 bringing in 820 dollars
<em>Number of child tickets bought + number of adult tickets bought = 110</em>
c + a = 110 ----- eqn 1
<em><u>Also we can frame a equation as:</u></em>
Number of child tickets bought x cost of each child ticket + number of adult tickets bought x cost of each adult ticket = 820

5c + 8a = 820 -------- eqn 2
Let us solve eqn 1 and eqn 2 to find values of "c" and "a"
From eqn 1,
a = 110 - c ------ eqn 3
Substitute eqn 3 in eqn 2
5c + 8(110 - c) = 820
5c + 880 - 8c = 820
-3c = - 60
c = 20
Therefore from eqn 3,
a = 110 - 20 = 90
a = 90
Therefore number of child tickets bought is 20
Answer:
it is D
Step-by-step explanation:
I know things dude. I got your back :-)
The equation would be .05x+50=100 Then you would solve for x
Answer: 19 booooooooooiii