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vova2212 [387]
3 years ago
14

Is 721 ft above sea level positive, zero,negative ?

Mathematics
1 answer:
mylen [45]3 years ago
6 0

Answer:

Well it is ABOVE sea level, so its positive.

Sea level would be considered zero, and if it was below sea level it would be considered negative.

I hope this helped you ♥  ♥

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In the equation 16x=128,is the value 8 a solution to this equation? Explain your reasoning by filling in the blanks.
GrogVix [38]

Answer:

yes

Step-by-step explanation:

The value 8 is the solution to the equation because plugging 8 into the equation in place of the unknown variable x like 16(8) will equal 128.

6 0
2 years ago
3/5 + 7/8 + 3/10
viva [34]

Answer:

1 3/5 - 5/6 = 23/30 ≅ 0.7666667

Feel free to correct if I am wrong. Hope this helps!

7 0
2 years ago
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mixas84 [53]

Answer:

?????????what is it???????

Step-by-step explanation:

7 0
2 years ago
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If x^2+2=3^2/3+3^-2/3 then prove that 3x^3+9x-8=0​
gregori [183]

Answer:

See below.

Step-by-step explanation:

x^2 + 2 = 3^2/3 + 3^-2/3

x^2 = 3^2/3 + 3^-2/3  - 2

x =  √(3^2/3 + 3^-2/3  - 2)

x = 0.748888296

Substitute for x  in  3x^3 + 9x - 8:

3( 0.748888296)^3 + 9( 0.748888296) - 8 = 0.

So it is proved.

6 0
3 years ago
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A surveyer wants to find the distance from points A and B and to an inaccessible point C. These three points form a triangle. Be
Vinil7 [7]

Answer:

42.8°

Step-by-step explanation:

The sine rule states that for a triangle with lengths of a, b and c and the corresponding angles which are opposite the sides as A, B and C, then the following rule holds:

\frac{a}{sin(A)}=\frac{b}{sin(B)}  =\frac{c}{sin(C)}

Given that points A, B and C forms a triangle with angle A = 65°, distance from A-to-C = 90 m and the distance from B to C = 120 m.

The distance from A to C is the side opposite to angle B. Hence let b =  distance from A to C = 90 m.

The distance from B to C is the side opposite to angle A. Hence let a =  distance from B to C = 120 m.

Therefore using sine rule:

\frac{a}{sin(A)}=\frac{b}{sin(B)}  \\\\\frac{120}{sin(65)}=\frac{90}{sin(B)}  \\\\sin(B)=\frac{90*sin(65)}{120} \\\\sin(B) =0.6797\\\\B=sin^{-1}(0.6797)\\\\B=42.8^o

7 0
2 years ago
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