Answer:
Step-by-step explanation:
From the given information;
We will realize that in the 2nd & 3rd equation, the integer "x" is missing.
So, the correct equation should be:
4x - 2 + 6z = 0
x - y - z = 0
2x - y + 3z = 0
By rearrangement; if we switch equation (1) and (2)
x - y - z = 0 ----- (1)
4x - 2 + 6z = 0 ------ (2)
2x - y + 3z = 0 ------ (3)
If we multiply equation (1) and add that to equation (2);
Then, we have:
x - y - z = 0
2y + 10z = 0
2x - y + 3z = 0
Also, if we multiply equation (1) by -2 and add that to equation (3), we have:
x - y - z = 0
2y + 10z = 0
y + 5z = 0
From above recent equation, if we swap equation (2) and (3);
x - y - z = 0
y + 5z = 0
2y + 10z = 0
Then, multiply equation (2) with -2, followed by adding it to equation(3);
Then:
x - y - z = 0
y + 5z = 0
0 = 0
Now, there exists no equation (3). Thus, let assume z = t to solve for x & y
y + 5z = 0
y = -5t
Similarly;
x - y - z = 0
x = -5t + t
x = -4t
Hence;
x = -4t; y = -5t; & z = t
