<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
Answer:
The first row
Step-by-step explanation:
Letters A,B,C,D
Answer:
Power
Base
Exponent
Repeated Multiplication
Step-by-step explanation:
On edge 2020
Answer:
−
8
5
=−0.62500
Step-by-step explanation:
I used something Imao-
Answer:
Step-by-step explanation:
A diameter of the circle.