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marissa [1.9K]
2 years ago
6

Solve the equation. Then check your solution.

Mathematics
2 answers:
swat322 years ago
6 0

Answer:

A

Step-by-step explanation:

Trust me

Rus_ich [418]2 years ago
3 0

Answer:

  • A. - 6

Step-by-step explanation:

<u>Solve the equation:</u>

  • 15(- 42x + 40) = 15 (-8x + 244)
  • - 42x + 40 = -8x + 244
  • 42x - 8x = 40 - 244
  • 34x = - 204
  • x = -204/34
  • x = -6

Correct choice is A

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Xelga [282]

Answer:B.

Step-by-step explanation:

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3 years ago
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There are 4 types of the questions on Mrs. Moore's English final exam. The percent of each type of the question is shown in the
Verdich [7]
Jesse, to answer this, we need to see the graph. I'd help if I could! You can message me if you post it! :D
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3 years ago
Drag the correct factors to the expression. Not all factors will be used. Use synthetic division to find all the factors of this
fiasKO [112]

The factors are therefore;  (4x – 3), (x + 3) and (x – 1)

<h3>What is a polynomial?</h3>

A polynomial is is a function that contains an algebraic term which is raised to a particular power.

  • If it is raised to power 1 it is linear
  • If it is raised to power 2 it is quadratic
  • If its is raised to power 3 it is cubic
  • If it i raised to power 3 it is quartic

Now we have;

4x³ + 5x² – 18x + 9

Thus we can write;

4x³ – 3x² + 8x² – 6x – 12x + 9

Using the factors;

x²(4x – 3) + 2x(4x² – 3) – 3(4x – 3)

Therefore;

(4x – 3)(x² + 2x– 3)

(4x – 3)(x² + 3x – x – 3)

(4x – 3)(x + 3)(x – 1)

The factors are therefore;  (4x – 3), (x + 3) and (x – 1)

Learn more about polynomials:brainly.com/question/21334281

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3 0
1 year ago
What is h(-8)=-2(-8+5)^2 +4
arlik [135]

Answer:

I got a fraction but, H= 7/4

3 0
2 years ago
What is the center of the ellipse x2+5y2–45=0?
jeka94

Answer:

Center is at (0,0)

Step-by-step explanation:

An equation of ellipse in standard form is:

\displaystyle{\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2} = 1

Where center is at point (h,k)

From the equation of \displaystyle{x^2+5y^2-45=0}. First, we add 45 both sides:

\displaystyle{x^2+5y^2-45+45=0+45}\\\\\displaystyle{x^2+5y^2=45}

Convert into the standard form with RHS (Right-Hand Side) equal to 1 by dividing both sides by 45:

\displaystyle{\dfrac{x^2}{45}+\dfrac{5y^2}{45}=\dfrac{45}{45}}\\\\\displaystyle{\dfrac{x^2}{45}+\dfrac{y^2}{9}=1}

Therefore, the center of ellipse is at (0,0) since there are no values of h and k.

8 0
2 years ago
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