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erik [133]
3 years ago
9

Solve for X 3(-2x-1)=2(x+5)

Mathematics
2 answers:
fredd [130]3 years ago
5 0
U need to use the distributive property ok? The u have to add or subtract the number on both sides bring it down and the you have to divide
fenix001 [56]3 years ago
4 0

Answer:

3(-2x-1) = 2(x+5)

-6x-3 = 2x+ 10

-13 = 8x | :8

-13/8 = x

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Okay let's see.
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The length of a rectangle is 5959 inches greatergreater than twice the width. if the diagonal is 2 inches more than the​ length,
lorasvet [3.4K]

Length: 2w + 59

width: w

diagonal: (2w + 59) + 2  = 2w + 61

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(2w + 59)² + (w)² = (2w + 61)²

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w = [-(b) +/- \sqrt{(b)^{2}  - 4(a)(c) }]/2(a)

 = [-(-4) +/- \sqrt{(-4)^{2}  - 4(1)(-240) }]/2(1)

   =  [4 +/- \sqrt{(16  + 960) }]/2        

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  = 1 +/- 2\sqrt{(61) }

since width cannot be negative, disregard  1 - 2√61

w = 1 + 2√61  ≈ 16.62

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I divided the two fractions & drew a model.

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