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3 years ago

14

-8x-2y=-22 16x+7y=17

1 answer:

Nataly [62]3 years ago

5 0

2(-8x-2y=-22)
16x+7y=17

-16x-4y=-44
16x+7y=17

3y=-27
y=-9

16x+7(-9)=17
16x+-63=17
16x=80
X=5

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bija089 [108]

The solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Solution:

Given equation:

$-2 x^{2}+y=-5$

Add $2 x^{2}$ on both sides.

$-2 x^{2}+y+2 x^{2}=-5+2 x^{2}$

$y=-5+2 x^{2}$ -------- (1)

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Equate (1) and (2).

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Add $3 x^{2}$ on both sides.

$-5+2 x^{2}+3 x^{2}=-3 x^{2}+5 +3 x^{2}$

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Add 5 on both sides.

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Divide by 5 on both sides, we get

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Taking square root on both sides, we get

$x=\sqrt{2}, x=-\sqrt{2}$

Substitute $x=\sqrt{2}$ in (1).

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Substitute $x=-\sqrt{2}$ in (1).

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$y=-5+4$

$y=-1$

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Answer:

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Step-by-step explanation:

A number m is such that when it is divided by 30, 36 and 45 the remainder is always 7.

We should first find the LCM of 30, 36 and 45

We get that the LCM of the three numbers is 280 (working attached).

So now;

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