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Elodia [21]
3 years ago
14

1. Y varies inversely with x. If y = 9 when x = -5, find the value of x when y=-6.

Mathematics
1 answer:
Gelneren [198K]3 years ago
3 0

Answer:

Step-by-step explanation:

1 )  Y∝ 1 / X

Y = k / X

Y = 9 , X = -5

Putting the values in the relation above

9 = k / - 5

k = -45

Y = - 45 / X

Put Y = - 6

- 6 = - 45 / X

X = - 45 / -6

= 7.5

2 )

Luke and Nora can peel 12 carrots in 5 minutes

in 1 minute Luke and Nora can peel 12 / 5 carrot

in 1 minute Luke alone   can peel 12/ 11 carrot .

In 1 minute Nora alone will peel (12 / 5 -  12/ 11  ) carrot

(12 / 5 -  12 / 11  )

= 2.4 - 1.1

= 1.3 carrot

In 1 minute Nora alone will peel 1.3 carrot

1.3 carrot in 1 minute

8 carrot in 8 / 1.3 minute

= 6.15 minutes.

In 1 minute Nora alone will peel 8 carrot in 6.15 minutes working alone.

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3,545(1+r)^n
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Find the 79th term of the following arithmetic sequence. 5,11, 17, 23...
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Answer:

the answer is 479.

Step-by-step explanation:

to make it simpler, pretend you start from 1. 1,7,so on. multiply six by 79, to get 474. but because you are starting from 5 and not 1, you have to add 5 on.

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3 years ago
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There are 1,200 students at Roosevelt middle school. There are 700 boys at the school. What percentage of the students at Roosev
Stella [2.4K]
Out of 1,200 students, 700 are boys. Therefore, the fraction would be \frac{700}{1200}.

To convert this into a percentage, divide 700 by 1,200.

\frac{700}{1200} = 0.583333 (or just 0.583 if you round)

Multiply 0.583 by 100 to get a percentage.

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4 0
3 years ago
1.What are the zeros of the polynomial function?
Lorico [155]
Let's to the first example:

f(x) = x^2 + 9x + 20

Ussing the formula of basckara

a = 1
b = 9
c = 20

Delta = b^2 - 4ac

Delta = 9^2 - 4.(1).(20)

Delta = 81 - 80

Delta = 1

x = [ -b +/- √(Delta) ]/2a

Replacing the data:

x = [ -9 +/- √1 ]/2

x' = (-9 -1)/2 <=> - 5

Or

x" = (-9+1)/2 <=> - 4
_______________

Already the second example:

f(x) = x^2 -4x -60

Ussing the formula of basckara again

a = 1
b = -4
c = -60

Delta = b^2 -4ac

Delta = (-4)^2 -4.(1).(-60)

Delta = 16 + 240

Delta = 256

Then, following:

x = [ -b +/- √(Delta)]/2a

Replacing the information

x = [ -(-4) +/- √256 ]/2

x = [ 4 +/- 16]/2

x' = (4-16)/2 <=> -6

Or

x" = (4+16)/2 <=> 10
______________

Now we are going to the 3 example

x^2 + 24 = 14x

Isolating 14x , but changing the sinal positive to negative

x^2 - 14x + 24 = 0

Now we can to apply the formula of basckara

a = 1
b = -14
c = 24

Delta = b^2 -4ac

Delta = (-14)^2 -4.(1).(24)

Delta = 196 - 96

Delta = 100

Then we stayed with:

x = [ -b +/- √Delta ]/2a

x = [ -(-14) +/- √100 ]/2

We wiil have two possibilities

x' = ( 14 -10)/2 <=> 2

Or

x" = (14 +10)/2 <=> 12
________________


To the last example will be the same thing.

f(x) = x^2 - x -72

a = 1
b = -1
c = -72

Delta = b^2 -4ac

Delta = (-1)^2 -4(1).(-72)

Delta = 1 + 288

Delta = 289

Then we are going to stay:

x = [ -b +/- √Delta]/2a

x = [ -(-1) +/- √289]/2

x = ( 1 +/- 17)/2

We will have two roots

That's :

x = (1 - 17)/2 <=> -8

Or

x = (1+17)/2 <=> 9


Well, this would be your answers.


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