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3 years ago

Can anybody help me answer this ASAP thank you

Mathematics

1 answer:

Anna11 [10]3 years ago

4 0

Step-by-step explanation:

$third \: term = ( \frac{1}{2} \times coefficient\: of \:x)^{2} \\ \\ = ( \frac{1}{2} \times \frac{ - 2}{7} )^{2} \\ \\ = ( \frac{ - 1}{7} )^{2} \\ \\ = \frac{1}{49}$

So, you need to add $\frac{1}{49}$ on both sides of the quadratic equation.

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Plεαse solve thanks!!!!

Gwar [14]

Answer:

1/12

Step-by-step explanation:

1/6x

1/2

1/12

its lined up just in case

4 0

3 years ago

Which inequality is shown in this graph

Katena32 [7]

ANSWER

$y \leqslant - 2x - 2$

EXPLANATION

The boundary line passes through (-2,2) and (0,-2).

The slope of this line is

$m = \frac{ - 2 - 2}{0 - - 2}$

$m = \frac{ - 4}{2} = - 2$

The y-intercept is , c=-2.

The slope-intercept form of this line is given by;

$y = mx + c$

We substitute values to obtain;

$y = - 2x - 2$

Since the lower half-plane is shaded the required inequality is

$y \leqslant - 2x - 2$

7 0

3 years ago

It takes Mike 60 minutes to vacuum a room, and Debbie 45 minutes.

elena55 [62]

Answer:

It takes Mike 15 more minutes to vacuum while it takes Debbie 15 more minutes to wash dishes

Step-by-step explanation:

Explain question properly pls.

3 0

2 years ago

Solve for x. Round to the nearest tenth, if necessary.

serg [7]

Answer:

x = 8.8

Step-by-step explanation:

take 20 degree as reference angle .the,

hypotenuse = OQ = x (hypotenuse is always opposite of 90 degree)

perpendicular(opposite) = PQ 3 (opposite of reference angle is perpendicular or also called as opposite)

base(adjacent) = OP (side which lies on the same line where 90 degree and reference angle)

using sin rule

sin 20 = opposite / hypotenuse

0.34 = 3 / x

x = 3/0.34

x = 8.82

x = 8.8

4 0

2 years ago

Read 2 more answers

Multiple polynomial the (x^3+3x^2+1)(3x^2+6x-2)

Mrrafil [7]

The product of given polynomials is: $3x^5+15x^4-16x^3-3x^2+6x-2$

Step-by-step explanation:

Given polynomials are:

$(x^3+3x^2+1)\\and\\(3x^2+6x-2)$

In order to multiply both polynomials, we will use the distributive property

So,

$= (x^3+3x^2+1)(3x^2+6x-2)\\=x^3(3x^2+6x-2)+3x^2(3x^2+6x-2)+1(3x^2+6x-2)\\=3x^5+6x^4-2x^3+9x^4+18x^3-6x^2+3x^2+6x-2$

Combining like terms

$=3x^5+6x^4+9x^4-2x^3+18x^3+3x^2-6x^2+6x-2\\=3x^5+15x^4-16x^3-3x^2+6x-2$

Hence,

The product of given polynomials is: $3x^5+15x^4-16x^3-3x^2+6x-2$

Keywords: Polynomials, variables

Learn more about polynomials at:

#LearnwithBrainly

6 0

3 years ago