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True [87]
3 years ago
12

Set up a system of linear equations, and then solve for the indicated quantities.

Mathematics
1 answer:
hichkok12 [17]3 years ago
7 0

9514 1404 393

Answer:

  • smaller: -4
  • larger: -1

Step-by-step explanation:

Substituting the given variables into the word problem, we have two equations:

  3x +3y = -15

  6x -3y = -21

Adding these equations eliminates y:

  9x = -36

  x = -4 . . . . divide by 9

Using this in the first equation, we have ...

  3(-4) +3y = -15

  -4 +y = -5 . . . . . divide by 3

  y = -1 . . . . . . . . . add 4

The smaller number is -4; the larger is -1.

You might be interested in
1. Ruth Lockwood earns $2,917 a month as a supervisor for Acme
soldi70 [24.7K]

Answer:

a. 25%

b. $1560

c. $130

Step-by-step explanation:

a.

If 75% is paid by company, the rest is paid by Ruth.

Out of 100%, 75% is paid by company, so Ruth pays 100 - 75 = 25%

b.

Per year, the total amount paid is 6240, but Ruth pas 25% of this. So,

25% = 0.25

To get the answer, we multiply 0.25 with 6240.

0.25 * 6240 = 1560

So, $1560 is paid by Ruth annually.

c.

Since 1560 is paid annually (in 12 months), each month Ruth has to pay:

1560/12 = $130

Hence, $130 is deducted each month from her paycheck

6 0
3 years ago
What two numbers multiply to -52 and add up to 24
harkovskaia [24]

Answer:

-2 and 26

Step-by-step explanation:

Multiply to -52:

-2 * 26= -52

Add to 24

-2+26= 24

8 0
3 years ago
Read 2 more answers
How do you solve this equation: -2m+3=|15+m|
Elden [556K]

Any number inside the modulus sign becomes positive. This means |15+m|=|-(15+m)|=|-15-m| and so we have,

-2m+3=|15+m| \Rightarrow \left \Big\{ {{-2m+3=15+m} \atop{-2m+3=-15-m}} \right

Solving these gives us

-2m+3=15+m \Rightarrow m=-4

-2m+3=-15-m \Rightarrow = m=18

However if we check the second solution in the original equation we obtain -2(18)+3=|15+18| \Rightarrow -33=33. This is false and so m=18 can't be a solution.

Therefore the only solution is m=-4.

(Note: I'm not sure why the second solution didn't work but when there's a modulus sign involved it always pays to check your final answers to be sure. I'll have a think about it but in case you find out before I do, I'd be interested to know in the comments.)

8 0
3 years ago
find the value of 10 times the square root of 2 over the square root of 5.. a. 2 b. 2 times the square root of 5. c. 2 the squar
Marizza181 [45]
\dfrac{10\sqrt2}{\sqrt5}=\dfrac{10\sqrt2\cdot\sqrt5}{\sqrt5\cdot\sqrt5}=\dfrac{10\sqrt{2\cdot5}}{5}=\boxed{2\sqrt{10}}\to\fbox{c.}
6 0
3 years ago
1011+111 in binary form
Ann [662]

Answer:

10010

Step-by-step explanation:

1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0

111=1(2)^2+1(2)^1+1(2)^0

So 1011+111 gives us:

1(2)^3+0(2)^2+1(2)^1+1(2)^0

+

1(2)^2+1(2)^1+1(2)^0

-----------------------------------------------------

Combine like terms:

1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0

1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace 2^0 with 1 and 2 with (2)^1:

1(2)^3+1(2)^2+(2)^2+(2)^1(1)

I want a 2^0 number:

1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0

Combine like terms:

1(2)^3+2(2)^2+1(2)^1+0(2)^0

2(2)^2=2^3:

1(2)^3+2^3+1(2)^1+0(2)^0

Combine like terms:

2(2)^3+1(2)^1+0(2)^0

We can rewrite the first term by law of exponents:

2^4+1(2)^1+0(2)^0

1(2)^4+1(2)^1+0(2)^0

So the binary form is:

10010

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

      1     0     1      1

+            1      1      1

------------------------------

     (1)    (1)    (1)

      1     0     1      1

+            1      1      1

------------------------------

     1 0    0     1       0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

8 0
3 years ago
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