(a). To calculate Y at equilibrium
Y = C + I + G
Y = 40 + 0.8(Y – 0 + 10 + 20)
Y = 350
(b). To calculate C, I and G at Equilibrium
C = 40 + 0.8 Y
Since Y = 350
C = 40 + 0.8(350)
C = 40 + 280
C = 320
I = 20
G = 10
(c).To find
equilibrium Y
Given,
EX = 4 + 3EP/P
IM = 8 + 0.1 (Y - T) - 2EP/P
E = 3
P = 1
P = 1.5
Y = 170
This sentence does not give us enough information or the needed information to know how many of each kind of fruit are put into the bag, but it does give the needed information to know how many ounces each piece of fruit weighed which was 4.75 oz per piece of fruit.
The ad was around 15 lines.
25.10/5.02 = 5
and then 5 * 3 = 15 lines
Let x be the shorter side, and y be the longer side
There would be 4 fences along the shorter side, and 2 fences along the longer side
4x + 2y = 800
Rewrite in terms of y:
y = 400 − 2x
The area of the rectangular field is
A = x*y
Replace Y with the equation above:
A = x(400 − 2x)
A = − 2x^2 + 400x
The area is a parabola that opens downward, the maximum area would occur at the parabola vertex.
At the vertex
x = −b/2a
= −400/[2(−2)]
= 100
y = 400 −2x
y = 400 -2(100)
y = 400-200
y = 200
The dimension of the rectangular field that maximize the enclosed area is 100 ft x 200 ft.
