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olga_2 [115]
3 years ago
10

Plz Help! 50 points and branliest if right!

Mathematics
2 answers:
Vesnalui [34]3 years ago
8 0
  1. This is the solution above........

SVETLANKA909090 [29]3 years ago
7 0

Answer: The answer is 8

Step-by-step explanation:

Because you multiply the length by width to get area you just divide the area by either the length or width to find the missing length.

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5A+10=200. Solve the problem
USPshnik [31]
Answer: A = 38

Steps:
5A = 200 - 10
5A = 190
A = 190/5
A = 38

I hope this helps :)
5 0
2 years ago
Read 2 more answers
Find the approximate value of the circumference of a circle with the given radius. use = 3.14. round your results to one more de
sveta [45]
The circumference of the circle is about 25.12 inches. Hope it help!
4 0
3 years ago
To change knots per hour, use the expression 1.15k, where k is the speed in in knots per hour. A plane is flying at 300 knots pe
Free_Kalibri [48]
1.15(300).
Substitute k for 300, since the plane is flying 300 knots per hour, and k=knots per hour.

1.15(300)=345 miles per hour
After multiplying, 300 by 1.15, you get 345 miles per hour. This is the speed of the plane from Knots to MPH (Miles Per Hour).
8 0
2 years ago
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My brain is rotting and so is my mental state
geniusboy [140]

Answer:

I'd recommend the photo math app

Step-by-step explanation:

it's easy to use and it can help

4 0
2 years ago
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In basketball, hang time is the time that both of your feet are off the ground during a jump. The equation for hang time is t =
const2013 [10]

Considering the hang time equation, it is found that Player 1 jumped 0.68 feet higher than Player 2.

<h3>What is the hang time equation?</h3>

The hang-time of the ball for a player of jump h is given by:

t = 2\left(\frac{2h}{32}\right)^{\frac{1}{2}}

The expression can be simplified as:

t = 2\sqrt{\frac{h}{16}}

For a player that has a hang time of 0.9s, the jump is found as follows:

0.9 = 2\sqrt{\frac{h}{16}}

\sqrt{\frac{h}{16}} = \frac{0.9}{2}

(\sqrt{\frac{h}{16}})^2 = \left(\frac{0.9}{2}\right)^2

h = 16\left(\frac{0.9}{2}\right)^2

h = 3.24 feet.

For a player that has a hang time of 0.8s, the jump is found as follows:

0.8 = 2\sqrt{\frac{h}{16}}

\sqrt{\frac{h}{16}} = \frac{0.8}{2}

(\sqrt{\frac{h}{16}})^2 = \left(\frac{0.8}{2}\right)^2

h = 16\left(\frac{0.8}{2}\right)^2

h = 2.56 feet.

The difference is given by:

3.24 - 2.56 = 0.68 feet.

More can be learned about equations at brainly.com/question/25537936

#SPJ1

3 0
2 years ago
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