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kogti [31]
3 years ago
6

5x/8 - 8 = 2x/3 How do I work this out ?

Mathematics
2 answers:
nekit [7.7K]3 years ago
6 0
First you would subtract 5x/8 from both sides so that you isolate x. to do that, find the common denominator of both fractions (15x/24 and 16x/24) and then subtract into get 1x/24. from there, you would multiply both sides by the reciprocal, or 24, to isolate x. that would be -8(24) = x, which is -192. therefore, x = -192.

i don’t know if this is right or not, but i hope it helped somehow!
fomenos3 years ago
3 0

For this case we must solve the following expression:

\frac {5x} {8} -8 = \frac {2x} {3}

Subtracting \frac {2x} {3} from both sides of the equation:

\frac {5x} {8} - \frac {2x} {3} -8 = 0

Adding 8 to both sides of the equation:

\frac {5x} {8} - \frac {2x} {3} = 8\\\frac {3 * 5x-8 * 2x} {8 * 3} = 8\\\frac {15x-16x} {24} = 8\\15x-16x = 24 * 8\\-x = 192\\x = -192

Answer:

x = -192

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The J.R. Ryland Computer Company is considering a plant expansion to enable the company to begin production of a new computer pr
Solnce55 [7]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data:

Medium-Scale Large-Scale

Expansion Profit Expansion Profit

x f(x) y f(y)

Low 50 0.2 0 0.2

Demand Medium 150 0.5 100 0.5

High 200 0.3 300 0.3

a. Compute the expected value for the profit associated with the two expansion alternatives.

Which decision is preferred for the objective of maximizing the expected profit?

Expected value for medium scale expansion profit :

Expected value (E) = Σ(X) * f(x)

Σ[(50 * 0.2) + (150 * 0.5) + (200 * 0.3)]

= 145

Expected value for Large scale expansion profit :

Expected value (E) = Σ(X) * f(x)

Σ[(0 * 0.2) + (100 * 0.5) + (300 * 0.3)]

= 140

Medium scale expansion profit is preferred as it has the highest expected value.

b. Compute the variance for the profit associated with the two expansion alternatives.

Which decision is preferred for the objective of minimizing the risk or uncertainty?

Variance (V) = Σ(X - E)² * f(x):

Variance for medium scale expansion profit :

V = [((50-145)^2 * 0.2) + ((150-145)^2 * 0.5) + ((200-145)^2 * 0.3) = 2725

Variance for Large scale expansion profit :

V = [((0-140)^2 * 0.2) + ((100-140)^2 * 0.5) + ((300-140)^2 * 0.3) = 12400

Smaller variance is required to minimize risk, Hence, choose the medium scale expansion profit.

3 0
3 years ago
What is 87 1/2 % of 540.72
Doss [256]

Answer:

6.18

Step-by-step explanation:

4 0
3 years ago
If a substance decays at a rate of 25% every 10 years, how long will it take 512 grams of the substance to decay to 121.5 grams
Juliette [100K]

Answer:

It will take 50 years to decay from 512 grams to 121.5 grams.

Step-by-step explanation:

The decay formula :

N=N_0e^{-\lambda t}

where

N= amount of substance after t time

N₀= initial of substance

t= time.

A substance decays at a rate 25% every 10 years.

So, remaining amount of the substance is = (100%-25%)= 75%

\frac{N}{N_0}=\frac{75\%}{100\%}=\frac{75}{100}=\frac34, t= 10

N=N_0e^{-\lambda t}

\Rightarrow \frac {N}{N_0}=e^{-\lambda t}

\Rightarrow \frac34 =e^{-\lambda .10}

Taking ln both sides

\Rightarrow ln|\frac34| =ln|e^{-\lambda .10}|

\Rightarrow ln|\frac34|=-10\lambda

\Rightarrow \lambda=\frac{ ln|\frac34|}{-10}

Now , N₀= 512 grams, N= 121.5 grams, t=?

N=N_0e^{-\lambda t}

\therefore 121.5=512e^{-\frac{ln|\frac34|}{-10}.t}

\Rightarrow 121.5=512e^{\frac{ln|\frac34|}{10}.t}

\Rightarrow \frac{121.5}{512}=e^{\frac{ln|\frac34|}{10}.t}

Taking ln both sides

\Rightarrow ln|\frac{121.5}{512}|=ln|e^{\frac{ln|\frac34|}{10}.t}|

\Rightarrow ln|\frac{121.5}{512}|={\frac{ln|\frac34|}{10}.t}

\Rightarrow t=\frac{ln|\frac{121.5}{512}|}{\frac{ln|\frac34|}{10}}

\Rightarrow t=\frac{10.ln|\frac{121.5}{512}|}{{ln|\frac34|}}

⇒t=50 years

It will take 50 years to decay from 512 grams to 121.5 grams.

8 0
4 years ago
Which one of these functions is a power function? A. F(x) = |x| B. F(x) = sin x C. F(x) = x^4 D. F(x) = 5x + 1 / x^2 - 1
Alex

Answer:

A F(x) it is the power function, make sure to take notes as well

4 0
3 years ago
Katie feeds her cat, Elmer, 2/3 of a cup of food each day. She buys a bag of cat food that contains 18 cups of dry
Natasha2012 [34]

Answer:

27

Step-by-step explanation:

Set up a proportion.

1 day / (2/3 cup) = x/ 18 cups            Cross Multiply

1 day * 18 cups = 2/3 cup * x            Multiply both sides by 3

1 day * 18 cups * 3 = 2x

54 day cups = 2x cups                    Divide by 2

54 day cups/2 cups = x

27 days (The cups cancel)

8 0
3 years ago
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