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sveticcg [70]
3 years ago
14

Which fraction is equivalent to

" alt="\frac{25}{35}" align="absmiddle" class="latex-formula">
A) \frac{2}{3}

B) \frac{20}{30}

C) \frac{3}{5}

D) \frac{5}{7}
Mathematics
1 answer:
Vinil7 [7]3 years ago
4 0

\dfrac{25}{35}=\dfrac{25:5}{35:5}=\dfrac{5}{7}\to\boxed{D)}

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8=Z/16<br><br><br> Hint: equation and rational coefficient
sergiy2304 [10]

Answer:

z=128

Step-by-step explanation:

z/16=8

z=8*16

z=128

8 0
3 years ago
Gloria has 4 ¼ gallons of fruit punch to share. Each serving is 1 pint. How many servings does she have to share?
Aloiza [94]

Answer:

D. 34 servings.

Step-by-step explanation:

1 gallon is 8 pints.

4.25 gallons * 8 pints = 34 servings of 1 pint each.

Hope this helps!

5 0
2 years ago
The picture has the question
AlladinOne [14]
It will b answer A. Because they all have equal parts
3 0
3 years ago
The ratio of 06 hours to 02 hours is written as
murzikaleks [220]

Ratios can be written in fraction form (1/2) or like this (1:2). According to your question, you could write it like 6/2 or 6:2. Be sure to simplify, by dividing the numbers by their greatest common factor. By simplifying by 2, your ratios simplify by 3:1 or 3/1. Hope this helped :)

5 0
3 years ago
Calculate the length of AB using Sine rule
vovikov84 [41]

Answer:

Approximately 22.2\; \rm m.

Step-by-step explanation:

By sine rule, the length of each side of a triangle is proportional to the sine value of the angle opposite to that side. For example, in this triangle \triangle ABC, angle \angle A is opposite to side BC, while \angle C is opposite to side AB. By sine rule, \displaystyle \frac{BC}{\sin{\angle A}} = \frac{AB}{\sin \angle C}.

It is already given that BC = 22.4\; \rm m and \angle A = 58^\circ. The catch is that the value of \angle C needs to be calculated from \angle A and \angle B.

The sum of the three internal angles of a triangle is 180^\circ. In \triangle ABC, that means \angle A + \angle B + \angle C = 180^\circ. Hence,

\begin{aligned}\angle C &= 180^\circ - \angle A - \angle B \\ &= 180^\circ - 58^\circ - 65^\circ \\ &= 57^\circ\end{aligned}.

Apply the sine rule:

\begin{aligned} & \frac{BC}{\sin{\angle A}} = \frac{AB}{\sin \angle C} \\ \implies & AB = \frac{BC}{\sin{\angle A}} \cdot \sin \angle C  \end{aligned}.

\begin{aligned}AB &= \frac{BC}{\sin{\angle A}} \cdot \sin \angle C \\ &= \frac{22.4\; \rm m}{\sin 58^\circ} \times \sin 57^\circ \\ &\approx 22.2\; \rm m\end{aligned}.

5 0
2 years ago
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