Answer:
so the first picture is it graphed without solving it and the second graph is the answer to it graphed
Step-by-step explanation:
Answer:
(0,-1)
Step-by-step explanation:
(0,-1) will work because when you plug them is it is equivalent to 4
Answer:
An event with probability 0 never occurs. An event with probability 1 occurs on every trial
Step-by-step explanation:
Answer:
29
Step-by-step explanation:
-9+21= 21
-12+4=-8
21-(-8)=29
identity used is
x³ + y³+ z³– 3xyz = (x + y + z) (x² + y² + z² – xy – yz – zx).
then use
(x+y+z)² = x²+y²+z²+2(xy+yz+xz)
225= 83 + 2(xy+yz+xz)
xy+yz+xz = (225-83)/2
xy+yz+xz= 142/2
xy+yz+xz= 71
ok
now use identity
x³ + y³+ z³– 3xyz = (x + y + z) (x² + y² + z² – xy – yz – zx).
now
x³ + y³+ z³– 3xyz = 15 (83 – xy – yz – zx).
= 15[83 - (71)]
= 15×12
=180
