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UNO [17]
1 year ago
12

Type the correct answer in the box use nummerals instead of words. if necessary use / for the faction bar

Mathematics
1 answer:
zzz [600]1 year ago
3 0

Answer: f(y) x g(y) = 1

Step-by-step explanation:

\frac{2y^3-y^2+2y-1}{y^3-y^2+y-1}\cdot \frac{2y^2-3y+1}{4y^2-4y+1}\\\\= \frac{4y^5-8y^4+9y^3-9y^2+5y-1}{4y^5-8y^4+9y^3-9y^2+5y-1} \\\\= \frac{(y-1)(2y-1)(2y-1)(y^2+1)}{(y-1)(2y-1)(2y-1)(y^2+1)} \\\\= 1

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Algebra pic for reference , thank u so much
blagie [28]
Well first you would substitute or plug in the values.
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5 0
3 years ago
Please help me im almost done with all of my work
Natasha2012 [34]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
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Rasek [7]
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6 0
2 years ago
Please help me! i dont know what to do... And my weekend depends on you
vladimir2022 [97]

Answer:

the signed number 7

Step-by-step explanation:

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7 0
3 years ago
A diamond today cost ten dollars more than twice what it cost last year.The sum of the cost (last year and this year) is $2500.
nadya68 [22]

Answer:

The cost of the diamond last year is x = $ 830

Step-by-step explanation:

Let the cost of diamond last year = x

the cost of diamond present year = y

Given that diamond today cost ten dollars more than twice what it cost last year.

⇒ y = 2 x + 10  ------ (1)

The sum of the cost (last year and this year) is  = $ 2500

⇒ x + y = $ 2500 -------- (2)

Put the value of y in equation (2) from equation (1), we get

⇒ 2 x + 10 + x = $ 2500

⇒ 3 x = 2490

⇒ x = $ 830

& y = 2500 - 830

⇒ y = $ 1670

Therefore the cost of the diamond last year is x = $ 830

6 0
3 years ago
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