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2 years ago

Type the correct answer in the box use nummerals instead of words. if necessary use / for the faction bar

Mathematics

1 answer:

zzz [600]2 years ago

3 0

Answer: f(y) x g(y) = 1

Step-by-step explanation:

$\frac{2y^3-y^2+2y-1}{y^3-y^2+y-1}\cdot \frac{2y^2-3y+1}{4y^2-4y+1}\\\\= \frac{4y^5-8y^4+9y^3-9y^2+5y-1}{4y^5-8y^4+9y^3-9y^2+5y-1} \\\\= \frac{(y-1)(2y-1)(2y-1)(y^2+1)}{(y-1)(2y-1)(2y-1)(y^2+1)} \\\\= 1$

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If the endpoints of AB have the coordinates A(9, 8) and B(-1, -2), what is the midpoint of AB?

pickupchik [31]

The midpoint, if the endpoints are (x₁,y₁) and (x₂,y₂):
$(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

$(9,8) \\
x_1=9 \\ y_1=8 \\ \\
(-1,-2) \\
x_2=-1 \\ y_2=-2 \\ \\
\frac{x_1+x_2}{2}=\frac{9-1}{2}=\frac{8}{2}=4 \\
\frac{y_1+y_2}{2}=\frac{8-2}{2}=\frac{6}{2}=3$

The midpoint of AB is (4,3).

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Answer:

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Step-by-step explanation:

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4 years ago

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Answer:

Step-by-step explanation:

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hope this helps

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