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UNO [17]
2 years ago
12

Type the correct answer in the box use nummerals instead of words. if necessary use / for the faction bar

Mathematics
1 answer:
zzz [600]2 years ago
3 0

Answer: f(y) x g(y) = 1

Step-by-step explanation:

\frac{2y^3-y^2+2y-1}{y^3-y^2+y-1}\cdot \frac{2y^2-3y+1}{4y^2-4y+1}\\\\= \frac{4y^5-8y^4+9y^3-9y^2+5y-1}{4y^5-8y^4+9y^3-9y^2+5y-1} \\\\= \frac{(y-1)(2y-1)(2y-1)(y^2+1)}{(y-1)(2y-1)(2y-1)(y^2+1)} \\\\= 1

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