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levacccp [35]
3 years ago
13

Helpppppp pleaseeeeee

Mathematics
1 answer:
Natalija [7]3 years ago
3 0

Select the second and fourth options.

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Answer this question please; number 5... show all work thank you
My name is Ann [436]

Answer:

rate of the plane in still air is 33 miles per hour and the rate of the wind is 11 miles per hour

Step-by-step explanation:

We will make a table of the trip there and back using the formula distance = rate x time

                 d              =            r       x       t

there

back

The distance there and back is 264 miles, so we can split that in half and put each half under d:

               d            =         r        x        t

there    132

back     132

It tells us that the trip there is with the wind and the trip back is against the wind:

           

              d           =        r         x        t

there     132        =    (r + w)

back      132       =     (r - w)

Finally, the trip there took 3 hours and the trip back took 6:

           

             d         =        r        *        t

there    132     =    (r + w)     *       3

back     132     =    (r - w)      *       6

There's the table.  Using the distance formula we have 2 equations that result from that info:

132 = 3(r + w)        and        132 = 6(r - w)

We are looking to solve for both r and w.  We have 2 equations with 2 unknowns, so we will solve the first equation for r, sub that value for r into the second equation to solve for w:

132 = 3r + 3w and

132 - 3w = 3r so

44 - w = r.  Subbing that into the second equation:

132 = 6(44 - w) - 6w and

132 = 264 - 6w - 6w and

-132 = -12w so

w = 11

Subbing w in to solve for r:

132 = 3r + 3(11) and

132 = 3r + 33 so

99 = 3r and

r = 33

7 0
3 years ago
Type SSS, SAS, ASA, SAA, or HL to<br> describe these triangles.
Viktor [21]

Answer:

ASA

Step-by-step explanation:

none needed [=

3 0
2 years ago
5. Earl runs 75 meters in 30 seconds. How many meters does Earl<br> run per second?
Rudik [331]

Answer:

He runs 2.5 meters per second

Step-by-step explanation:

all you do is divide 75/30 and the answer is 2.5.

8 0
3 years ago
Help just stuck on this one
erastova [34]
I think 1 sorry if it is wrong
7 0
3 years ago
a plane flying with the wind travels 630 mi in 1.5hrs. Flying against the wind , the plane travels 1120 mi in 4hrs. Find the rat
Flauer [41]
\bf \begin{cases}&#10;r=\textit{rate of the plane}\\&#10;w=\textit{rate of the wind}\\&#10;\end{cases}&#10;\\\\&#10;&#10;\begin{array}{ccccllll}&#10;&distance&rate&time(hrs)\\&#10;&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\&#10;\textit{with wind}&630&r+w&1\frac{1}{2}\\&#10;\textit{against wind}&1120&r-w&4&#10;\end{array}&#10;

\bf thus  \begin{cases}&#10;630=(r+w)1\frac{1}{2}\to 630=(r+w)\frac{3}{2}&#10;\\\\&#10;1120=(r-w)4\\&#10;--------------\\&#10;630=(r+w)\frac{3}{2}\implies 630\cdot \frac{2}{3}=r+w\\&#10;420=r+w\implies \boxed{420-w}=r\\&#10;--------------\\&#10;thus\\&#10;--------------\\&#10;1120=(r-w)4\implies 1120=4r-4w&#10;\\\\&#10;1120=4(\boxed{420-w})-4w&#10;\end{cases}&#10;

solve for "w", to find the wind's speed rate,

so hmmm what's the plane's rate?  well 420 - w = r  :)
5 0
2 years ago
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