QUESTION 6
1 answer:
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The value of the variable x = 6 and y = 5. Then the position vector of P will be 6i + 5j.
<h3>What is the equation of a line passing through two points?</h3>The equation of line is given as
y = mx + c
Where m is the slope and c is the y-intercept.
PQRS is a parallelogram. the position vector of Q R and S are 5i +7j, -3i-8j and -4i-6j.
Then the point of Q, R, and S will be (5, 7), (-3, -8), and (-4, -6).
Let the point P be (x, y).
We know that the slope of the line QS and PQ will be same and line is passing through (-3, -8).
y = 1.444x + C
-8 = 1.444 (-3) + C
C = -3.667
Then the equation will be
y = 1.444x – 3.667 …1
The slope of the line PQ and RS will be same and line is passing through (5, 7).
y = -2x + D
7 = -2 (5) + D
D = 17
Then the equation will be
y = -2x + 17 …2
By solving equation 1 and 2, we have
x = 6 and y = 5
Then the position vector of P will be
⇒ 6i + 5j
The graph is given below.
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The diameter of the semicircle is 16 feet.
He calculates that he needs to buy abut 25.12 feet of fencing.
To find amount of fencing we find the circumference of semicircle
Circumference of semicircle =
Where d is the diameter of the circle
d= 16 given and value of pi is 3.14
Circumference of semicircle =
=25.12 + 16 = 41.12 feet
Scott's calculation was wrong because he forgot to add the diameter d
Circumference of circle is half way of circle plus the diameter of circle.
Correct amount of fencing = 41.12 feet