Okay so.
A is 4.95
B is 4.95
C is 4.95
D is 4.95
E is 0.495
So I guess E is the Answer! :)
Answer: Zero; 9; -18
Step-by-step explanation:
An additive inverse always adds up to zero. 9 is the opposite of -9, and -18 is the opposite of 18
Answer: c
explanation:
Its f(x) but flipped and intersects at y = -3
good luck!
Answer:
a) 
And if we solve for
we got:

b) False
The reason is because we don't satisfy the following relationship:

We have that:

c) False
In order to satisfy independence we need to have the following condition:

And for this case we don't satisfy this relation since:

Step-by-step explanation:
For this case we have the following probabilities given:

Part a
We want to calculate the following probability: 
And we can use the total probability rule given by:

And if we solve for
we got:

Part b
False
The reason is because we don't satisfy the following relationship:

We have that:

Part c
False
In order to satisfy independence we need to have the following condition:

And for this case we don't satisfy this relation since:

Answer:
64
Step-by-step explanation: