Answer:
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Step-by-step explanation:
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Answer:
<h2>A. -2</h2>
Step-by-step explanation:
![\det\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] =ad-bc\\\\\det\left[\begin{array}{ccc}3&-5\\1&1\end{array}\right] =(3)(1)+(-5)(1)=3-5=-2](https://tex.z-dn.net/?f=%5Cdet%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%20%3Dad-bc%5C%5C%5C%5C%5Cdet%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-5%5C%5C1%261%5Cend%7Barray%7D%5Cright%5D%20%3D%283%29%281%29%2B%28-5%29%281%29%3D3-5%3D-2)
Hello :
the solution is : <span>(3, -1)
put x= 3 and y = -1
you have : 3-(-1) = 4 and 3+(-1) = 2 ..... right</span>
Here are a couple I found:
<u>Similarities</u>:
- They have the same y-intercept of (0,5).
- They are both in slope-intercept form.
<u>Differences</u>:
- The line of y = -13x + 5 "falls" from left to right. The line of y = 2x + 5 "rises" from left to right.
- They have different x-intercepts. (y = 2x + 5 intersects (-
, 0) while y = -13x + 5 intersects at (
, 0)
<u></u>
<u>Explanation</u>:
Slope-intercept form is y = mx + b, and by looking at the equations, they both already fit that format, with m as their slope and b as their y-intercept. Also, since they both have a 5 as that "b," their y-intercepts are the same: (0,5).
As for differences, we can see that the coefficient in place of that "m" is positive in y = <u>2x</u> + 5 and negative in y = <u>-13x</u> + 5. Therefore, one line would rise due to their slope being positive and one would fall due to their slope being negative. They also have two different x-intercepts, which we can calculate by substituting 0 in place of the y, then isolating x.
Undefined slope
slope=rise/run
if run=0, we get an undefined slope
means that it does go left or right, only up and down
the equaiton will be x=something
x intercept is -7 so the equation is x=-7