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sweet-ann [11.9K]
3 years ago
12

Simplify the expression:Two-thirds divided by (negative 4) minus (one-sixth minus StartFraction 8 over 6 EndFraction)

Mathematics
2 answers:
AURORKA [14]3 years ago
6 0

Answer:

1

Step-by-step explanation:

Brainliest please

juin [17]3 years ago
4 0

we have been given an expression \frac{\frac{2}{3}}{-4}-\left(\frac{1}{6}-\frac{8}{6}\right). We are asked to simplify our given expression.

Using quotient rule \frac{\frac{a}{b}}{c}=\frac{a}{bc}, we will get:

\frac{2}{3\cdot -4}-\left(\frac{1}{6}-\frac{8}{6}\right)

\frac{2}{-12}-\left(\frac{1}{6}-\frac{8}{6}\right)

Now, we will combine like terms:

\frac{2}{-12}-\left(\frac{1-8}{6}\right)

\frac{2}{-12}-\left(\frac{-7}{6}\right)

-\frac{2}{12}+\frac{7}{6}

-\frac{1}{6}+\frac{7}{6}

Let us combine like terms:

\frac{-1+7}{6}

\frac{6}{6}=1

Therefore, our expression simplifies to 1.

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The distance between B and B' will be the same as distance between A and A'.

= sqrt ( (5-1)^2 + ( 1 - -2)^2)

= sqrt (16 + 9)

= 5 units answer

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Evaluate 13-0.5w+6x when w=10 and x=1/2
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Ok so first you need to put w and x in the equation —-> 13-0.5(10)+6(1/2) and now you just solve -0.5 times 10 is -5 so 13-(-5)+6(1/2) now multiply 6 times 1/2 which is 3 so now we have 13-(-5)+3= 21
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A squar has a premeter of 12x+52 units which expression represents the side length of the square in units?
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Afreen says, "I am thinking of 3 consecutive numbers. The first is a multiple of 4, the second is a multiple of 5 and the third
IgorLugansk [536]

Answer:

The 3 ses that we found are:

{4, 5, 6}

{64, 65, 66}

{124, 125, 126}

Step-by-step explanation:

3 consecutive numbers are written as:

n, (n + 1), (n + 2)

We know that the first one is a multiple of 4.

Then n is a multiple of 4:

n = k*4

where k is an integer.

The second one is a multiple of 5, then:

(n + 1) = j*5

where j is an integer.

The last one is a multiple of 6.

(n + 2) = p*6

where p is an integer.

We want to find 3 sets.

The first one is trivial:

n = 4

n + 1 = 5

n + 2 = 6

4 is a multiple of 4

5 is a multiple of 5

6 is a multiple of 6.

Now let's find a set that is not trivial.

First, remember that all the multiples of 5 end with a 0 or a 5,

Then we can look for a value n, that is multiple of 4, and that has a last units digit equal to 4 (then the next one will have a units digit and will be multiple of 5)

For example, 4*6 = 24

24 is a multiple of 4.

The next number is 24 + 1 = 25, which is multiple of 5.

The next number is 25 + 1 = 26, which is not multiple of 6.

So let's try again.

4*11 = 44, is a multiple of 4.

The next number is 44 + 1 = 45

45 is a multiple of 5.

The next number is 45 + 1 = 46, which is not multiple of 6

So we need to try with another set.

4*16 = 64, is a multiple of 4.

The next number is 64 + 1 = 65, which is multiple of 5.

The next number is 66, which is multiple of 6:

6*11 = 66

Then the set:

n = 64

n + 1 = 65

n + 2 = 66

Is a possible set.

Now we can keep trying this, we can see that the next set  has the numbers:

n = 4*31  = 124 is a multiple of 4.

The next number, is 124 + 1 = 125, which is a multiple of 5.

The next number is 125 + 1 = 126, which is multiple of 6

6*21 = 126

Then the set:

n = 124

n + 1 = 125

n + 2 = 126

Is another possible set.

The 3 ses that we found are:

{4, 5, 6}

{64, 65, 66}

{124, 125, 126}

7 0
3 years ago
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