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BlackZzzverrR [31]
3 years ago
12

What is 8546 divided by 2 [8546/2]

Mathematics
2 answers:
shepuryov [24]3 years ago
4 0

Answer:

4273

Step-by-step explanation:

kvv77 [185]3 years ago
3 0
8546/2 = 4273

Hope this helps!

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F(x)=x^3+9x^2+23x + 15
Airida [17]
This is what I got hope it helps!

4 0
2 years ago
Help with this question please!
vova2212 [387]

<em>V = 120 in^3</em>

<u><em>Here is why:</em></u>

The volume formula for a pyramid is:

V=\frac{1}{3}Bh

The B stands for the area of the base, which in this case is a right triangle. We will find the area of the right triangle first, then plug it into the equation.

The area formula for a triangle is:

A=\frac{1}{2}bh

Plug in the numbers.

A=\frac{1}{2}*9*10

A = 45

Now we have found the area of B, we can plug it into the volume formula for the pyramid.

V=\frac{1}{3}*45*8

V = 120 in^3

7 0
3 years ago
10.1 and 10.15 witch one is greater
RUDIKE [14]

Answer:

10.15

Step-by-step explanation:

Subtract:

10.15 - 10.1 = 0.05

10.15 is greater than 10.1 by 0.05

~

6 0
3 years ago
Read 2 more answers
In rectangle PQRS, PR = 18x – 28 and QS = x + 380. Find the value of x and the length of each diagonal.
chubhunter [2.5K]

Answer:

x = 24, PR = 404, QS = 404

Step-by-step explanation:

PR and QS are both diagonals of the rectangle. The diagonals of a rectangle bisect each other and are of equal length. Thus, we can say:

PR = QS

18x - 28 = x + 380

Solving for x, we get:

18x - x = 380 + 28

17x = 408

x = 408/17

x = 24

Thus, PR = 18(24) - 28 = 404  and  QS = 24 + 380 = 404

Third choice is right.

7 0
2 years ago
Cosx+1/sin^3x=cscx/1-cosx
ANTONII [103]
<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).

 </span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).

 </span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.

 </span>
<span>I hope this helps! </span>
8 0
3 years ago
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