Answer:
X² - 14x + 48= 0
Step-by-step explanation:
To find the quadratic equation well have to look for the root of the equation.
So the roots are at x= 6 and x= 8
The quadratic curve didn't pass the origin .
It intercepted the x axis at 6 and 8 and that's the roots.
So our equation is
(X-6)(x-8)= x²-8x -6x +48
X² - 14x + 48= 0
5.6 is 5.63 rounded to the nearest tenth
is this somthing that your looking for?
Answer:
See explanation below
Step-by-step explanation:
Find the value of x in each of the following
1) x-1+5√x-1+3=0
5√x-1 = -x -2
Square both sides
25(x-1) = (-x-2)^2
25(x-1) = x^2+4x + 4
25x-25 = x^2+4x + 4
x^2 +4x + 4 - 25x + 25 = 0
x^2 - 21x + 29 = 0
x = 21±√21²-4(29)/2
x = 21±√441-116/2
x = 21±√325/2
x = 21±18.03/2
x = 21+18.03/2 and 21-18.03/2
x = 19.515 and 1.485
4) x^4-64=0
x^4 = 64
![x = \sqrt[4]{64}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B4%5D%7B64%7D)
x = 2.83