Suppose that the scores, X, on a college entrance examination are normally distributed with a mean score of 560 and a standard d
eviation of 40. A certain university will consider for admission only those applicants whose scores fall among the top 67% of the distribution of scores. Find the minimum score an applicant must achieve in order to receive consideration for admission to the university.
1 answer:
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Answer:
B) μD = 0.60 ± 0.10(1.397)
Step-by-step explanation:
The confidence interval is given by:
Where
MD=60
n=9
df=n-1=8
Then the confidence interval is
μD=0.60±1.397*(0.3/√9)
μD=0.60±0.10*(1.397)
Answer:
3 cm
Step-by-step explanation:
Set up an equation that solves for the surface area, "112" :
10(2)+10(2)+2x+2x+10x+10x = 112
20+20+4x+20x = 112
24x+40=112
24x=72
x=3
So, 3 cm.
<h2>pi divided by four</h2>
Step-by-step explanation:
Let the angle in degrees be
Let the angle in radians be
If is the angle in degrees and
is the angle in radians,
It is given that the
So,