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vichka [17]
3 years ago
12

Suppose that the scores, X, on a college entrance examination are normally distributed with a mean score of 560 and a standard d

eviation of 40. A certain university will consider for admission only those applicants whose scores fall among the top 67% of the distribution of scores. Find the minimum score an applicant must achieve in order to receive consideration for admission to the university.

Mathematics
1 answer:
12345 [234]3 years ago
7 0

Answer:

  543

Step-by-step explanation:

The 33rd percentile corresponds to a score of 542.4. In order for a score to be within the top 67%, it must be above that value. The least integer above that value is 543.

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GrogVix [38]
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I also think a constant could be the variable next to the coefficient. Which would be y and x (next to 7 and 18).

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7 0
4 years ago
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Answer:

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3 years ago
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3 years ago
Solve for X: -3 |2x+6| = -12
Kobotan [32]
Hello there!

-3| 2x + 6| = -12
2x + 6 = -12/-3
2x + 6 = 4
Solve absolute value
We know that 2x + 6 = 4 or 2x + 6 = -4
We have two possibilities to solve this.

1)
2x + 6 = 4
2x = 4 - 6
2x = -2
Divide both sides by -2
2x/-2 = -2/-2
x = 1


2) 
2x + 6 = -4
2x = -4 - 6
2x = -10
Divide both sides by 2
2x/2 = -10/2
x = -5

Answer : X = -1 or X = -5

A+ Guaranteed! 

3 0
3 years ago
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IrinaVladis [17]

Answer:

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Step-by-step explanation:

divide by 3 on both sides

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8 0
3 years ago
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