All categories

3 years ago

Can someone help me? This is my 4th time trying to get help. Thanks! :)

Mathematics

2 answers:

Alexeev081 [22]3 years ago

7 0

Answer:

a. 12 people per minute

b. 95 people entered the hall in that time

c. 19 people per minute

d. 12 people per minute so c is greater than 19 minutes to 12 minutes

Step-by-step explanation:

a. You just divide 48 by 4: 12

b. You would subtract 239 by 144 and you would get 95

c. You would divide 95 by 5 which you would get 19

d. You would subtract 275 by 239 which would be 36 than you would divide by 3 and you would get 12 so c would be greater

Anni [7]3 years ago

4 0

Answer:

Step-by-step explanation:

A. the rate in which people fill up the hall in the first for minutes is 12

B. 95 people

C. the rate in which people fill up the hall between 10 and 15 minutes is 19

D. it was greater

You might be interested in

The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require

grigory [225]

Answer:

142.2 meters.

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.

Let us find total surface area of box using surface area formula of cuboid.

$\text{Total surface area of cuboid}=2(lb+bh+hl)$ , where,

$l$ = Length of cuboid,

$b$ = Breadth of cuboid,

$w$ = Width of cuboid.

$\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)$

$\text{Total surface area of box}=2(2520+432+840)$

$\text{Total surface area of box}=2(3792)$

$\text{Total surface area of box}=7584$

Therefore, the total surface area of box will be 7584 square cm.

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

$\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}$

$80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2$

$\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=14220\text{ cm}$

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}$

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}$

$\text{ Length of canvass}=142.20\text{ m}$

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

5 0

4 years ago

Triangles PIC Included

ZanzabumX [31]

Answer:

sin70° = x/6

Step-by-step explanation:

When we draw out our picture and triangle, we should see that our angle is on the ground 70°, the height x is across from the angle and is the vertical leg up, and that our hypotenuse is equal to 6:

sin70° = x/6

6 0

4 years ago

Read 2 more answers

Compare a perpendicular bisector and an altitude of a triangle

lara31 [8.8K]

Perpendicular bisectors are segment that passes through the mid point of a triangle, while altitude is the perpendicular distance from the base to the opposite vertex.

3 0

3 years ago

Name 3 rays in this geometric construction E A D B Your answer

almond37 [142]

Do you have a picture or anything that you could show us?

5 0

3 years ago

The area of a soccer field is ( 24x^2 + 100x + 100) m^2. The width of the field is (4x + 10)m. What is the length?

Firdavs [7]

The answer should be (12x + 20) (2x + 5)

4 0

4 years ago