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inn [45]
2 years ago
13

5 feet 4 feet What is the area? 15 square feet 20 square feet 10 square feet

Mathematics
1 answer:
sesenic [268]2 years ago
7 0

it is 20

use the formula W x L =A

width (5) length (4)

5 x 4 is 20

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Sean’s house is currently worth $188,900 according to the realtor house prices and Shawn‘s neighborhood will increase by 4.8% ev
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.048t = 188,900 (This side will have the total increase after being divided by % and X amount of years)
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Plz help... geometry volume, density
Ivenika [448]

From what I'm understanding of these questions, the biggest thing you need to answer these is the formulas for cylinders and triangular prisms. I'm not sure what the quantities are for either question so I'm going to work with made up numbers to give examples for the formulas. For number 2 with the cylinder, let's consider the formula first:

π × r2 × h    <em>OR    </em>pi (3.14) times radius squared times height

If you have the height and you have pi, all you need to take is the doubled radius (aka multiply it by 2) and plug that back into the formula. For the sake of an example, I'm going to make up the number 2 for the radius and 6 for the height. Here's what that would look like:

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For number 3, reducing something by 1/2 means dividing by 2. Let's consider the formula and then work through another example:

1/2 x b x h x l   <em>OR </em>   1/2 times base times height times length

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4 0
3 years ago
at a barbeque there are four cans of coke for every 5 cans of sprite the has 20 cans of coke how many cans of sprite are there
Zepler [3.9K]
Coke : sprite 
  4     :   5
 (x5)     (x5)
  20   :  25


--------------------------------------------------------------------------------------------
Answer: There are 25 cans of sprite.
--------------------------------------------------------------------------------------------
6 0
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Step-by-step explanation:

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Marina86 [1]

Answer:

0.416 au

Step-by-step explanation:

Let y1=8sin(x) and y2=8cos(x), we must find the area between y1 and y2

\int\limits^\pi _0{(8cos(x)-8sin(x))} \, dx = 8\int\limits^\pi _0{(cos(x)-sin(x))} \, dx =\\8(sin(x)+cos(x)) evaluated(0-\pi )=\\8(sin(\pi )-sin(0))+8(cos(\pi )-cos(0))=\\8(0.054-0)+8(0.998-1)=8(0.054)+8(-0.002)=0.432-0.016=0.416

3 0
3 years ago
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