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BaLLatris [955]
3 years ago
7

When is it useful to guess check to solve mathematical problems?

Mathematics
1 answer:
Ad libitum [116K]3 years ago
8 0

Answer:

often one of the first strategies that students learn when solving problems. This is a flexible strategy that is often used as a starting point when solving a problem, and can be used as a safety net, when no other strategy is immediately obvious.

Step-by-step explanation:

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Find the nth term of this number sequence.<br> 1,7,13,19...
masya89 [10]

Answer:

This sequence is arithmetic, and the next term is 25

Step-by-step explanation:

The common difference of the sequence is 6, so the next term is 19+6=25.

The difference between the consecutive terms is constant => sequence is arithmetic.

<u>7-1=6</u>

<u>13-7=6</u>

<u>19-13=6</u>

6 0
2 years ago
Read 2 more answers
Samantha has 4 1/2 gallons of lemonade for her daughter’s birthday party. Each gallon of lemonade contains 1.5 grams of fat. How
Lubov Fominskaja [6]

Answer:

6.75 grams

Step-by-step explanation:

Total amount of lemonade with Samantha =  4 1/2 gallons

         = (4*2 + 1)/2 gallons = 9/2 gallons = 4.5 gallons

Amount of fat in 1 gallon of lemonade = 1.5 grams

To find amount of fat in 4.5 gallons lemonade

we multiply both side of equation with 4.5

Amount of fat in 1*4.5 gallon of lemonade = 1.5*4.5  grams = 6.75 grams

Thus,

there is  6.75 grams of fat in  all the lemonade Samantha has for the party

3 0
3 years ago
The number of bikes sold each year, in thousands, in a city since 2004 is shown by the graph below, where x represents the numbe
fgiga [73]

Answer: Your answer will be A

Hope this helps


Step-by-step explanation:


4 0
3 years ago
What is the solution to the following system?
ahrayia [7]
(8, 40, 32) is the answer
4 0
3 years ago
Read 2 more answers
What is the radius of a sphere with a volume of 1/6 pie
Yakvenalex [24]

Answer:

\large\boxed{the\ radius\ R=\dfrac{1}{2}}

Step-by-step explanation:

The formula of a volume of a sphere:

V=\dfrac{4}{3}\pi R^3

We have

V=\dfrac{1}{6}\pi

Substitute:

\dfrac{4}{3}\pi R^3=\dfrac{1}{6}\pi        <em>divide both sides by π</em>

\dfrac{4}{3}R^3=\dfrac{1}{6}          <em>multiply both sides by 3</em>

3\!\!\!\!\diagup^1\cdot\dfrac{4}{3\!\!\!\!\diagup_1}R^3=3\!\!\!\!\diagup^1\cdot\dfrac{1}{6\!\!\!\!\diagup_2}

4R^3=\dfrac{1}{2}          <em>divide both sides by 4</em>

R^3=\dfrac{1}{2}:4\\\\R^3=\dfrac{1}{2}\cdot\dfrac{1}{4}\\\\R^3=\dfrac{1}{8}\to R=\sqrt[3]{\dfrac{1}{8}}\\\\R=\dfrac{\sqrt1}{\sqrt8}\\\\R=\dfrac{1}{2}

3 0
3 years ago
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