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WARRIOR [948]
4 years ago
13

Please help me with problem 1.

Mathematics
1 answer:
ANEK [815]4 years ago
4 0

People are getting in contact with hackers to help them clear student loans, change your grades  contact thunderbirdhack AT gmail DOT com 

he help me.

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Mαkє α 10 tσ 15 mínutє lєѕѕσn αвσut Writing Linear Function
gavmur [86]

yes its esy do it im a tell you how ot

8 0
3 years ago
Marisol sells wedding cakes. She charges a flat fee of $245 to make the wedding cake, plus an additional $120 per tier of cake.
leva [86]

Answer:

120x + 245 = y

x = number of additional tiers

(edited to be in the proper order)

8 0
3 years ago
The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t and has a half-life of 3.
blagie [28]

Answer:

N(t) =N_o (\frac{1}{2})^{\frac{t}{t_{1/2}}}

Where t_{1/2}= 3.3 hr represent the half life and the intial amount would be N_o = 1

And we want to find the time in order to have a 95% of decay so we can set up the following equation:

0.05 = 1 (0.5)^{t/3.3}

If we apply natural log on both sides we got:

ln(0.05) = \frac{t}{3.3} ln (0.5)

And solving for t we got:

t= 3.3 *\frac{ln(0.05)}{ln(0.5)}= 14.26

So then would takes about 14.26 hours in order to have  95% of the lead to decay

Step-by-step explanation:

For this case we can define the variable of interest amount of Pb209 and for the half life would be given:

N(t) =N_o (\frac{1}{2})^{\frac{t}{t_{1/2}}}

Where t_{1/2}= 3.3 hr represent the half life and the intial amount would be N_o = 1

And we want to find the time in order to have a 95% of decay so we can set up the following equation:

0.05 = 1 (0.5)^{t/3.3}

If we apply natural log on both sides we got:

ln(0.05) = \frac{t}{3.3} ln (0.5)

And solving for t we got:

t= 3.3 *\frac{ln(0.05)}{ln(0.5)}= 14.26

So then would takes about 14.26 hours in order to have  95% of the lead to decay

4 0
3 years ago
D=4ft plz help
posledela

Answer:

i don't understand the question there's

no pic

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
4. On the day Alex was born, his father invested $5000 in an account with a 1.2% annual growth rate.
sergij07 [2.7K]

Answer:

A)    A(t) = 5000(1 + 0.012)t

B)    A(t) = 106260

Step-by-step explanation:

A) 5000 is the initial amount, 1 + 0.012 is the interest rate, and t represents the years.

B) When we plug 21 into the equation,  we get 106260.

I hope this helps!

7 0
3 years ago
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