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chubhunter [2.5K]
3 years ago
13

4y=x 3x-y=70 how to solve this problem using substitution

Mathematics
1 answer:
diamong [38]3 years ago
3 0
4y=x
3(4y)-y=7012y-y=70
11y=70
y=70/11
4(70/11)=x
280/11=x
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What is 44.5443495 rounded to the nearest thousand
prohojiy [21]

Answer:

Step-by-step explanation:

To the nearest thousand the answer is 0.

If you meant thousandth then the second 4 to the right of the decimal point occupies the thousandth place. so that 4 is followed by a 3, that 4 is not changed.

The answer is 44.544

but it does depend on what you meant.

7 0
3 years ago
The number of flaws per square yard in a type of carpet material varies with mean 1.4 flaws per square yard and standard deviati
oksian1 [2.3K]
According to the Central Limit Theorem, the distribution of the sample means is approximately normal, with the mean equal to the population mean (1.4 flaws per square yard) and standard deviation given by:
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3 years ago
Which values are within the range of the piecewise-defined function? f(x) = StartLayout enlarged left-brace 1st Row 1st column 2
Otrada [13]

Answer:

the answer is below frum ed

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
Which shows the numbers in order from least to greatest?
gavmur [86]
So just convert to a common form
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to conver 1 and 3/7 to decimal, just divide 3 by 7 using a calculator
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5 0
3 years ago
Help please with this question
choli [55]

Answer:

They lose about 2.79% in purchasing power.

Step-by-step explanation:

Whenever you're dealing with purchasing power and inflation, you need to carefully define what the reference is for any changes you might be talking about. Here, we take <em>purchasing power at the beginning of the year</em> as the reference. Since we don't know when the 6% year occurred relative to the year in which the saving balance was $200,000, we choose to deal primarily with percentages, rather than dollar amounts.

Each day, the account value is multiplied by (1 + 0.03/365), so at the end of the year the value is multiplied by about

... (1 +0.03/365)^365 ≈ 1.03045326

Something that had a cost of 1 at the beginning of the year will have a cost of 1.06 at the end of the year. A savings account value of 1 at the beginning of the year would purchase one whole item. At the end of the year, the value of the savings account will purchase ...

... 1.03045326 / 1.06 ≈ 0.9721 . . . items

That is, the loss of purchasing power is about ...

... 1 - 0.9721 = 2.79%

_____

If the account value is $200,000 at the beginning of the year in question, then the purchasing power <em>normalized to what it was at the beginning of the year</em> is now $194,425.14, about $5,574.85 less.

7 0
3 years ago
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