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3 years ago

Can someone help me? I’m confused.

Mathematics

2 answers:

jonny [76]3 years ago

8 0

The answer is 3x10^12 also can i get brainliest please??

vazorg [7]3 years ago

7 0

Answer:

answer is 300. .........................

You might be interested in

Bonnie deposits $70.00 into a new savings account

xz_007 [3.2K]

Answer

$79.45

Use the <em>simple interest formula</em>

A= P(1+rt)

A = 70(1+0.045×3)

And you solve, which gives you 79.45

8 0

2 years ago

Azlyn can ride her horse 15.2 miles per hour. She is in an endurance race that is 76 miles

Tema [17]

Step-by-step explanation:

Remember, math is a language

when you see per think fractions

15.2 miles per hour = 15.2 miles / 1 hour

since this is a fraction, Units can cancel just like numbers

To cancel miles and be left with hours rearrange the fraction

1 hour / 15.2 miles

then multiply by 72 miles

$\frac{1hour}{15.2miles} \times 72miles$

the miles cancel and youre left with hours!

so youd write and solve 72 / 15.2

3 0

3 years ago

*URGENT ALGEBRA 2* Anyone know these answers? Will award brainliest.

stiv31 [10]

Correct Answer:
Second option

Solution:
The given sequence is:

2.2, 6.6, 11, ...

If we observe the sequence it is an Arithmetic Sequence as the difference between two consecutive terms is the same.

6.6 - 2.2 = 4.4
11 - 6.6 = 4.4

First we find the general term for this sequence.

$a(n)= a_{1}+(n-1)d$

$a_{1}=$ first term = 2.2
d = 4.4

So,

$a(n) = 2.2 +(n-1)*4.4 \\ \\ 
a(n) = 2.2 + 4.4n - 4.4 \\ \\ 
a(n) = 4.4n - 2.2$

This general term will be placed inside the summation sign with limits from 1 to 5 to give the sum of first 5 terms of the given sequence. So the correct answer is Second Option

6 0

3 years ago

A ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is h-48t -16t^2.

Marat540 [252]

Answer:

36 feet.

Step-by-step explanation:

We have been given that a ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is $h(t)=-48t -16t^2$ . We are asked to find the maximum height of the ball.

We can see that our given equation is a downward opening parabola, so its maximum height will be the vertex of the parabola.

To find the maximum height of the ball, we need to find y-coordinate of vertex of parabola.

Let us find x-coordinate of parabola using formula $x=-\frac{b}{2a}$ .

$x=-\frac{-48}{2(-16)}$

$x=-\frac{48}{32}$

$x=-\frac{3}{2}$

So, the x-coordinate of the parabola is $-\frac{3}{2}$ . Now, we will substitute $x=-\frac{3}{2}$ in our given equation to find y-coordinate of parabola.

$h(t)=-48t -16t^2$

$h(-\frac{3}{2})=-48(-\frac{3}{2})-16(-\frac{3}{2})^2$

$h(-\frac{3}{2})=-24(-3)-16(\frac{9}{4})$

$h(-\frac{3}{2})=72-4*9$

$h(-\frac{3}{2})=72-36$

$h(-\frac{3}{2})=36$

Therefore, the maximum height of the ball is 36 feet.

3 0

3 years ago

Required information An article presents a new method for timing traffic signals in heavily traveled intersections. The effectiv

Natasha2012 [34]

Answer:

$652.6-2.01\frac{311.7}{\sqrt{50}}=563.997$

$652.6+2.01\frac{311.7}{\sqrt{50}}=741.203$

So on this case the 95% confidence interval would be given by (563.997;741.203)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=652.6$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=311.7 represent the sample standard deviation

n=50 represent the sample size

Soltuion to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=50-1=49$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,49)".And we see that $t_{\alpha/2}=2.01$

Now we have everything in order to replace into formula (1):

$652.6-2.01\frac{311.7}{\sqrt{50}}=563.997$

$652.6+2.01\frac{311.7}{\sqrt{50}}=741.203$

So on this case the 95% confidence interval would be given by (563.997;741.203)

6 0

3 years ago