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uranmaximum [27]
3 years ago
13

HELP NEEDED,THANK YOU find all real zeros and complex of each function f(x)=x(4x-6)(x+1)(3x+5).SHOW WORK!!!

Mathematics
1 answer:
lisov135 [29]3 years ago
4 0

Answer:

x=0, 3/2, -1, -5/3

Step-by-step explanation:

The x-axis interception points of x(4x-6)(x+1)(3x+5): (0, 0), (3/2, 0), (-1, 0), (-5/3, 0)

The y-axis interception points of x(4x-6)(x+1)(3x+5): (0,0)

So the answer is 0, 3/2, -1, and -5/3.

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3 years ago
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2 years ago
3(5b-1)=5<br> solve for b<br><br> 4(3y-1)=20<br> solve for y
Gnom [1K]
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7 0
3 years ago
Find tan(450-a), If <br><img src="https://tex.z-dn.net/?f=%20%5Ctan%28a%29%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20" id="TexFormula1"
Inessa05 [86]

Answer:

tan(450-a)=5\sqrt{3}-8

Step-by-step explanation:

We know that:

tan(a-b)=\frac{tan(a)-tan(b)}{1+tan(a)tan(b)}

tan(450-a)=\frac{tan(450)-tan(a)}{1+tan(450)tan(a)}

Remember:

450°=360°+60°

and:

tan(a)=\frac{1}{2}

Thus:

tan(450-a)=\frac{tan(60)-tan(a)}{1+tan(60)tan(a)}\\\\

Then:

tan(450-a)=5\sqrt{3}-8

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2 years ago
Which expression is equivalent to −16y+13 ?
iragen [17]

Answer:

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
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