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uranmaximum [27]
3 years ago
13

HELP NEEDED,THANK YOU find all real zeros and complex of each function f(x)=x(4x-6)(x+1)(3x+5).SHOW WORK!!!

Mathematics
1 answer:
lisov135 [29]3 years ago
4 0

Answer:

x=0, 3/2, -1, -5/3

Step-by-step explanation:

The x-axis interception points of x(4x-6)(x+1)(3x+5): (0, 0), (3/2, 0), (-1, 0), (-5/3, 0)

The y-axis interception points of x(4x-6)(x+1)(3x+5): (0,0)

So the answer is 0, 3/2, -1, and -5/3.

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Angie and Becky each completed a separate proof to show that the measures of vertical angles AKG and HKB are equal. Who complete
Helga [31]

Answer:

Becky, because her justification for the second statement should be "definition of supplementary angles" rather than "angle addition postulate."

Step-by-step explanation:

Becky completed the proof incorrectly because her justification for the second statement is not totally correct.

Angle addition postulate does not really apply here, as the sum of 2 angles may not give you exactly 180°.

However, the second statement, m<AKG + m<GKB = 180° and m<GKB + m<HKB = 180°, can be justified by the "Definition of Supplementary Angles".

The sum of supplementary angles = 180°.

Therefore, Becky completed the proof incorrectly.

6 0
3 years ago
Subtract the sum of a^2 − 2ab + b^2 and 2a^2 + 2ab + b^2 from the sum of a^2 − b^2 and a^2 + ab + 3b^2
solniwko [45]

Answer:

-a^2 + ab

Step-by-step explanation:

(a^2 - 2ab +b^2) + (2a^2 + 2ab + b2) = 3a^2 + 2b^2

(a^2 - b^2) + (a^2 + ab + 3b^2) = 2a^2 + 2b^2 + ab

subtract the first part from the second part:

(2a^2 + 2b^2 + ab) - (3a^2 + 2b^2) =    -a^2 + ab

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5,908.66 is<br> 5,908.71
Vikki [24]

5,908.71

Step-by-step explanation:

7 0
3 years ago
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