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MissTica
3 years ago
6

What is the slope of a horizontal line? 0 undefined 1 -1

Mathematics
2 answers:
LenaWriter [7]3 years ago
3 0

the slope of a horizontal line is zero

umka21 [38]3 years ago
3 0

<u>Answer:</u>

Zero

<u>Step-by-step explanation:</u>

When a line is horizontal or you can say parallel to the x-axis, its slope is zero.

The reason being that there is no change in the value of y because the value of x is constant at each point of the line.

Slope = (change in y) / (change in x)

On the contrary, the slope of the line which is vertical or parallel to the y-axis has an undefined slope.

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PQ has endpoints P(-3,2) and Q(3,-2). Find the coordinates of the midpoint of PQ
hodyreva [135]

Answer:

(0,0)

Step-by-step explanation:

For this, you need to use the midpoint formula.

(-3) + 3                      2 + (-2)

--------------      ,       ----------------

     2                               2

This leads to:

-3 + 3 = 0 -> 0/2

x = 0

3 + (-3) = 0 -> 0/2

The answer is:

(0, 0)

6 0
1 year ago
A company sold 3,000 computers in one month, but 12 were returned. If 3,500 were sold the next month, the company would expect 1
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8 0
3 years ago
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Divide using synthetic division. ( x^4-12x^2-9)/(x+3)
Firdavs [7]

Answer:

x^3 - 3x^2 - 3x + 9 + (-36/(x+3))

OR

x^3 - 3x^2 - 3x + 9 - (36/(x+3))

Step-by-step explanation:

First set the divisor equal to 0:

x + 3 = 0

Subtract 3 from both sides

x = -3

This is what you'll divide the dividend by in synthetic division.

Take the coefficents of each term in the dividend. Do not forget the 0 placeholders:

x^4 + 0x^3 - 12x^2 + 0x -9

Coefficents: 1. 0.  -12. 0 -9.

Please see the image for the next steps.

The remainder is -36. Put the remainder over the divisor and add it to the polynomial (shown in image)

-36/(x+3)

6 0
3 years ago
Please help this question.
sergejj [24]

Answer:

a). 59.049°C

b). 2.1179 seconds

Step-by-step explanation:

Expression representing the final temperature after decrease in temperature of the metal from 100°C to T°C is,

T = 100(0.9)^{x}

where x = duration of cooling

a). Temperature when x = 5 seconds

T = 100(0.9)⁵

  = 59.049

  ≈ 59.049°C

b). If the temperature of the metal decreases from 100°C to 80°C

Which means for T = 80°C we have to calculate the duration of cooling 'x' seconds

80 = 100(0.9)^{x}

0.8 = (0.9)^{x}

By taking log on both the sides

log(0.8) =log[(0.9)^{x}]

-0.09691 = x[log(0.9)]

-0.09691 = -0.045757x

x = \frac{0.09691}{0.045757}

x = 2.1179

x ≈ 2.1179 seconds

3 0
3 years ago
At the market 8 batteries cost 10 dollars how much will 6 cost
NemiM [27]
Answer: 4.8
Why: 8/10=.8
.8x6=4.8
4 0
3 years ago
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