Answer:
The answer is 18 percent, or 9/50.
Step-by-step explanation:
We first convert the chance of rain on Monday into a fraction.
60%=60/100=3/5.
We then convert the chance of rain on Tuesday into a fraction.
30%=30/100=3/10.
Because the two events are independent(i.e. If it rains on Tuesday doesn't depend on if it rains on Monday) we multiply them together to get the probability they both happen. That chance is:
3/5 * 3/10=(3*3)/(5*10)=9/50(fraction form)=18/100=18%(percent form)
We are given the first term and the common ratio, this means they belong to a geometric series.
For the given series:
Each term of the geometric series is obtained by multiplying the previous term by common ratio.
So the next terms will be:
-4.5, -6.75, -10.125, -15.1875, -22.78125
The general formula for the G.P would be:
On plotting the series, the result will be like this:
Let
x--------------> total volume of a glass
we know that
(4/7)x-70=(2/4)x------------> (4/7)x-70=(1/2)x--------> 2*(4/7)x-2*70=x
(8/7)x-140=x
<span>multiplied by 7 the expresion
</span>7*(8/7)x-7*140=7*x-----------> 8x-980=7x--------> x=980 cm³
the answer is
<span>the total volume of the glass is 980 cm</span>³
The area bounded by the 2 parabolas is A(θ) = 1/2∫(r₂²- r₁²).dθ between limits θ = a,b...
<span>the limits are solution to 3cosθ = 1+cosθ the points of intersection of curves. </span>
<span>2cosθ = 1 => θ = ±π/3 </span>
<span>A(θ) = 1/2∫(r₂²- r₁²).dθ = 1/2∫(3cosθ)² - (1+cosθ)².dθ </span>
<span>= 1/2∫(3cosθ)².dθ - 1/2∫(1+cosθ)².dθ </span>
<span>= 9/8[2θ + sin(2θ)] - 1/8[6θ + 8sinθ +sin(2θ)] .. </span>
<span>.............where I have used ∫(cosθ)².dθ=1/4[2θ + sin(2θ)] </span>
<span>= 3θ/2 +sin(2θ) - sin(θ) </span>
<span>Area = A(π/3) - A(-π/3) </span>
<span>= 3π/6 + sin(2π/3) -sin(π/3) - (-3π/6) - sin(-2π/3) + sin(-π/3) </span>
<span>= π.</span>
Answer:
L.H.S.
= (cos5a.sin2a-cos4a.sin3a)/ (sin5a.sin2a-cos4a.cos3a)
Multiply numerator and denominator by 2.
= 2(cos5a.sin2a - cos4a.sin3a) / 2(sin5a.sin2a - cos4a.cos3a)
= (2cos5a.sin2a - 2cos4a.sin3a)/
(2sin5a.sin2a - 2cos4a.cos3a) = [sin(5a+2a)-sin(5a-2a)-sin(4a+3a)
+sin(4a-3a)]/[cos(5a-2a)-cos(5a+2a)-sin(4a-3a) +cos(4a+3a)]
= (sina - sin3a)/(cso3a-cosa)
= (-2cos2a.sina)/(-2sin2a.sina)
= cos2a/sin2a
= cot2a
= R.H.S.
