dy/dx = 8(8x - 5)(4x² - 5x )^ 7
differentiate using the ' chain rule '
dy/dx = 8(4x² - 5x)^ 7 × d/dx (4x² - 5x)
= 8(4x² - 5x)^ 7 × (8x - 5)
= 8(8x - 5)(4x² - 5x)
Can someone help me fill out 1-6
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dy/dx = 8(8x - 5)(4x² - 5x )^ 7
differentiate using the ' chain rule '
dy/dx = 8(4x² - 5x)^ 7 × d/dx (4x² - 5x)
= 8(4x² - 5x)^ 7 × (8x - 5)
= 8(8x - 5)(4x² - 5x)