Answer:
y'(t)=ky(t)(100-y(t))
Step-by-step explanation:
The rate of change of y(t) at any time is the derivative of y with respect to time y, y'(t)
If y(t) is the percent of the population advocating war at time t
then 100-y(t) is the percent of the population not advocating war
The product of the percentage of the population advocating war and the percentage not advocating war would be
y(t)(100-y(t))
If the rate of change of y(t) at any time is proportional to the product of the percentage of the population advocating war and the percentage not advocating war, then
y'(t)=ky(t)(100-y(t))
where <em>k is the constant of proportionality
</em>
Step-by-step explanation:
Longest side of cuboid: 7cm
Height of cylinder:
2 × 7 = 14 cm
Volume of cuboid:
7x3x4=84
Volume of cylinder:

Surface area of the cylinder:


=128 cm^2
Answer:
1. 94.25 is the surface area, 94.25 to 56.55 is the ratio of surface area to volume
2.138.23 is the surface area 138.23 to 113.1 is the ratio of surface area to volume
The answer would be 5 + 15i/2.
1. 5 + 3i/2 + 6i
2. 5 + (3/2i + 6i)
3. 5 + 15i/2.
Answer:
The equation of the circle can be written as:
Step-by-step explanation:
The general equation of a circle with center
and radius
is:

In our example, we know
, as we just have to make sure we need determine
.

As the circle passes through (10, 14), that pair of values for x and y must satisfy the equation. So we have:






Thus the equation of the circle can be written as:
