First we will find the interest on:
P = $235 principal
t = 2 years
r = 0.1415 annual rate
A = future value
I = A - P the interest
A = P(1 + r)^t
A = 235(1 + 0.1415)^2
A = $306.21
I = A - P
I = $306.21 - $235
I = $71.21
the interest was $71.21.
Next lets find the lifetime cost value:
Lifetime cost value = 306.21 + 5*1.56*52 + 5*0.78*52 = $914.61 (considering that 1 year = 52 weeks)
Now lets find the percentage what percentage the interest is of the lifetime cost:
(71.21/914.61)*100 = 7.79%
<span>← Previous Problem<span>Next Problem →</span></span>
Answer:
the quotient is 6x^2 - 16x + 16, and the remainder is just 4
Step-by-step explanation:
The polynomial 6x^3-10x^2+20 has coefficients {6, -10, 0, 20}. Division by the binomial x + 1 requires that we use -1 as the divisor. The synthetic division setup becomes:
-1 / 6 -10 0 20
-6 16 -16
-----------------------------
6 -16 16 4
Taking the coefficients {6, -16, 16}, we write the quotient as
6x^2 - 16x + 16, and the remainder as just 4.
A ratio between is like 52
Answer:
-11xy
Step-by-step explanation:
Subtracting a negative means adding.
-14xy - (-3xy) = -14xy + 3xy = -11xy
