Answer:
The answer :
<em>Bob spend $160</em><em>.</em>
<em>Josh spe</em><em>nd</em><em> </em><em>$80</em><em>.</em>
<em>Ralp</em><em> </em><em>spend</em><em> </em><em>$</em><em>2</em><em>0</em><em>.</em>
For the first one it would be C.
9514 1404 393
Answer:
- 75 adult tickets
- 125 child tickets
Step-by-step explanation:
Let 'a' represent the number of adult tickets sold. Then (200-a) is the number of child tickets sold, and the revenue is ...
8a +5(200 -a) = 1225
3a = 225 . . . . . . . . . . subtract 1000, simplify
a = 75 . . . . . . . . . . . . .divide by 3
200 -a = 125
75 adult ($8) and 125 child ($5) tickets were sold.
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<em>Additional comment</em>
The question asked here is "how many tickets did Kay sell?" The second line of your problem statement tells you the answer: "Kay sold 200 tickets ...". We have assumed that you are interested in the breakdown of tickets sold, even though that is not the question that is asked here.
Answer:
<h3>15</h3>
Step-by-step explanation:
<h2>you need to find the lcf(least common factor) of the two numbers which is 15</h2>
Answer:
Draw a pie chart looking wheel with 30% and 70% and spin the wheel three times and see what it lands on each time
Step-by-step explanation: