Answer:
Step-by-step explanation:
3.
ACE, BCE, DCE, FCE
4. BCF
supplementry means to form an 180 angle(straight line) which bcf and acf form.
5. You have to do it
6. Right
7.
Using the same rule as in 4. We can say bce and ace are supplementar.
Answer:
9.8
Step-by-step explanation:
use the formula
distance=✓[{x2-x1}+{y2-y1}]
P = 3
n = 5
N = 15
<span><span><span>x </span><span>¯ </span></span> </span>
= 16
<span><span>SST</span> </span>
= <span><span>∑n(x−<span><span>x </span><span>¯ </span></span><span><span>) </span><span>2 </span></span></span> </span>
<span><span>SST</span> </span>
= <span><span>5(12−16<span><span>) </span><span>2 </span></span>+5(16−16<span><span>) </span><span>2 </span></span>+11(20−16<span><span>) </span><span>2 </span></span></span> </span>
= 160
<span><span>MST</span> </span>
= <span><span><span><span>SST</span><span>p−1</span> </span> </span>
</span>
<span><span>MST</span> </span>
= <span><span><span>160<span>3−1</span> </span> </span>
</span>
= 80
<span><span>SSE</span> </span>
= <span><span>∑(n−1)<span><span>S </span><span>2 </span></span></span> </span>
SSE = 4*4 + 4*1 + 4*16
= 84
<span><span>MSE</span> </span>
= <span><span><span><span>SSE</span><span>N−p</span> </span> </span>
</span>
<span><span>MSE</span> </span>
= <span><span><span>84<span>15−3</span> </span> </span>
</span>
MSE = 7
<span>F </span>
= <span><span><span><span>MST</span><span>MSE</span> </span> </span>
</span>
<span>F </span>
= <span><span><span>807 </span> </span>
</span>
= 11.429
Answer:
5 packs of markers and 2 packs of crayons
Step-by-step explanation:
they will both have 50
Answer:
28/9
Step-by-step explanation:
If the roots are J and K, then:
3 (x − J) (x − K) = 0
3 (x² − (J+K)x + JK) = 0
So if we factor out the leading coefficient:
3x² − 2x − 4 = 0
3(x² − 2/3x − 4/3) = 0
The coefficient of the second term is the sum of the roots:
J + K = 2/3
And the constant is the product of the roots:
JK = -4/3
If we take the sum of the roots and square it:
(J + K)² = (2/3)²
J² + 2JK + K² = 4/9
And subtract twice the product:
J² + K² = 4/9 − 2JK
J² + K² = 4/9 − 2(-4/3)
J² + K² = 4/9 + 8/3
J² + k² = 28/9