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____ [38]
3 years ago
12

A bank employee notices an abandoned checking account with a balance of $412.if the bank charges a $4 monthly fee for the accoun

t, the function b=412-4m. When will the bank account balance be 0?
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
3 0
Here's what I'd do. If the account loses $4 per month, and it currently has $412, then do 412/4, which is 103 months. So in 103 months, or about 8 1/2 years, the bank account will be out of money.
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Answer: Both

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We know heard similar since they have congruent angle measures in corresponding spots.
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mixer [17]
|4| - |-5|
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3 years ago
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What is the best way to solve this
Komok [63]
Make 2 equations one for the price and one for quantity.  so first set x = AA and y= AAA. for price 37= 1x+.75y. now for the quantity we have x+y=42. Now we can solve by subtracting the equation for price from the equation for quantity and we get .25y =5. solving this we get y= 20. Now we plug that value back in and solve for x. 22 double A's and 20 triple A's.
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Step-by-step explanation:

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The following back to back stemplot represents the amount a sample of students spent on their last haircut. Because there are si
krek1111 [17]

The 5 - number summary of the distribution obtained from the boxplot is :

  • Minimum = 20
  • Maximum = 85
  • Lower quartile = 35
  • Median = 44
  • Upper quartile = 58
  • Outlier = 100

Firstly, we need to extract the values for the amount spent by females :

20, 25, 25, 35, 37, 38, 39, 43, 45, 46, 50, 53, 60, 70, 85, 100

The five number summary include ;

  • Minimum, lower Quartile, Median, Upper Quartile and Maximum values.

Rearranging the data in ascending order :

20, 25, 25, 35, 37, 38, 39, 43, 45, 46, 50, 53, 60, 70, 85, 100

The boxplot clearly and easily gives the five number summary of the distribution :

  • Minimum = 20 (starting point of the whisker)
  • Lower quartile = 35 (starting point of the box)
  • Median = 44 (vertical line in between the box)
  • Upper quartile = 58 (endpoint of the box)
  • Maximum = 85 (endpoint of the upper whisker).

Outlier :

  • Lower boundary = LOWER QUARTILE - (1.5 × IQR)
  • Upper boundary = UPPER QUARTILE + (1.5 × IQR)
  • IQR = UPPER QUARTILE - LOWER QUARTILE
  • IQR = (58 - 35) = 23

Lower boundary = 35 - (1.5 × 23) = 0.5

Upper boundary = 58 + (1.5 × 23) = 92.5

  • The point denoted by a dot on the boxplot is an outlier = 100

Hence, values lesser than 0.5 or greater than 92.5 are outliers.

Therefore, 100 is an outlier.

Learn more : brainly.com/question/24582786

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