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ELEN [110]
3 years ago
9

What is thw radius of a circle given by the equation x^2+y^2-2x+8y-47=0

Mathematics
1 answer:
Arlecino [84]3 years ago
8 0

x^2 + y^2 - 2x + 8y - 47 = 0

x^2 + y^2 - 2x + 8y = 47

(x^2 - 2x) + (y^2 + 8y) = 47

(x^2 - 2(1)x) + (y^2 + 2(4)y) = 47

(x^2 - 2(1)x + 1^2) + (y^2 + 2(4)y + 4^2) = 47 + 1^2 + 4^2

(x - 1)^2 + (y + 4)^2 = 64 = 8^2

r=8



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nadezda [96]

Yes, I would play the game, because the probability of winning is 13/18.

Probability:

Probability refer the possible occurrence of any particular event.

Given,

A game where two players each throw two dice each. if any one die matches the other, you win a dollar. if there is no match, you lose a dollar.

Here we need to find whether we able to play this one or not.

To find that one, first, we have to identify the winning scenarios,

Let us consider five winning scenarios. Lets represent the dice outcomes as A, B, C, and D, where your dice are A and B and the other player's are C and D. The five scenarios are:

1) A = B

2) A = C

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We know that the total possible outcomes is 6^4. We can go through each scenario and count the possible outcomes. We must be careful to avoid overcounting.

Based on this,

The probability that none match is

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=> 360 / 1296

=> 5 / 18

So, probability of winning is,

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=> 13/18.

So, based on the probability the chance of winning is high. So, we can play it.

To know more about Probability here.

brainly.com/question/11234923

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Answer:

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