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s2008m [1.1K]
2 years ago
15

Jesus Christ is coming soon, Believe in him and get saved, Muhammad is dead, Buddha is dead, Krishna is dead, But Jesus rose fro

m the dead and I don't say this in a hateful way to anyone, but Jesus can change your life like he changed mine, Jesus is coming back soon, Repent and Get right with God
Mathematics
2 answers:
WINSTONCH [101]2 years ago
8 0

Answer:

PREACH IT I've witnessed his miracles first hand

yulyashka [42]2 years ago
5 0

Amen, I agree with you. I've been in the deep with myself for way too long now... but now I gave myself to God and he changed my life forever.

You might be interested in
TRUE or FALSE: Your boat travels 480 miles in 20 hours. That is the same rate as 860 miles in 40 hours.
Morgarella [4.7K]

Answer:

false

Step-by-step explanation:

860 divided by 2 is 430 NOT 480

5 0
3 years ago
Read 2 more answers
A population of bees is decreasing. The population in a particular region this year is 1,250. After 1 year, it is estimated tha
8_murik_8 [283]
To model this situation, we are going to use the decay formula: A=Pe^{rt}
where 
A is the final pupolation
P is the initial population 
e is the Euler's constant
r is the decay rate 
t is the time in years

A. We know for our problem that the initial population is 1,250, so P=1250; we also know that after a year the population is 1000, so A=1000 and t=1. Lets replace those values in our formula to find r:
A=Pe^{rt}
1000=1250e^{r}
e^{r}= \frac{1000}{1250}
e^{r}= \frac{4}{5}
ln(e^{r})=ln( \frac{4}{5} )
r=ln( \frac{4}{5} )
r=-02231

Now that we have r, we can write a function to model this scenario:
A(t)=1250e^{-0.2231t}.

B. Here we are going to use a graphing utility to graph the function we derived in the previous point. Please check the attached image.

C. 
- The function is decreasing
- The function doe snot have a x-intercept 
- The function has a y-intercept at (0,1250)
- Since the function is decaying, it will have a maximum at t=0: 
A(0)=1250e^{(-0.2231)(0)
A_{0}=1250e^{0}
A_{0}=1250
- Over the interval [0,10], the function will have a minimum at t=10:
A(10)=1250e^{(-0.2231)(10)
A_{10}=134.28

D. To find the rate of change of the function over the interval [0,10], we are going to use the formula: m= \frac{A(0)-A(10)}{10-0}
where 
m is the rate of change 
A(10) is the function evaluated at 10
A(0) is the function evaluated at 0
We know from previous calculations that A(10)=134.28 and A(0)=1250, so lets replace those values in our formula to find m:
m= \frac{134.28-1250}{10-0}
m= \frac{-1115.72}{10}
m=-111.572
We can conclude that the rate of change of the function over the interval [0,10] is -111.572.

7 0
3 years ago
I would really appreciate some help.
VLD [36.1K]
2 to the power of 61 is = 2305843009213694000

then just minus that by 1 and divide it by 3. if it’s divisible then it’s a multiple of 3.
7 0
2 years ago
Please solve the following problem
kirza4 [7]

Answer:

x = 27

Step-by-step explanation:

Given

\frac{x}{9} = 3

Multiply both sides by 9 to clear the fraction

x = 9 × 3 = 27

5 0
3 years ago
30 POINTS FOR BRAINLIEST ANSWER!!!!!!!​
skad [1K]
I think b not sure it’s the only one that makes sense
6 0
3 years ago
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