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Aleks04 [339]
3 years ago
5

Need help with pythgoream theorem

Mathematics
1 answer:
Fantom [35]3 years ago
5 0
Upper Left for certain.
Lower right. You can check it out using
a^2 + b^2 = c^2
14^2 + 48^2 = 50^2
196 + 2304 =? 2500
2500 = 2500 This checks out to being true. I don't think there are any others.
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In the figure below, points A, B, and C are ______ points because they lie on the same line.
Nutka1998 [239]

Answer:

A, B, C are Collinear points

Step-by-step explanation:

5 0
3 years ago
A farmer has a square plot of land he needs defense he walked to the diagonal of the plot of land and found it to be 80 yards ho
andre [41]

Answer: i think the answer is 320

Step-by-step explanation:

i say 320 because a square has 4 sides and there is 80 yards so all i did is multiply 80 x 4 = 320

7 0
2 years ago
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PLEASE HELP ASAP!!!! BRAINLIEST ANSWER AWAITS YOU +30 POINTS!!
tester [92]
C is the correct answer



Hope this helps :D
8 0
3 years ago
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Which expressions are equivalent to 3x+3(x+y)3x+3(x+y)3, x, plus, 3, left parenthesis, x, plus, y, right parenthesis ? Choose al
wariber [46]

Answer: Choise A and Choise B.

Step-by-step explanation:

Given the following expression:

3x+3(x+y)

You can simplify it in order to find equivalent expressions.

Appying the Distributive Property, you get:

3x+(3)(x)+(y)(3)=3x+3x+3y

So:

1. If you add the like terms, you get this equivalent expression:

3x+3x+3y=6x+3y

2. But if you factor out 3, you get the following equivalent expression:

3x+3x+3y=3(x+x+y)

Therefore, the expression shown in Choice A and Choise B are equivalents to the expression 3x+3(x+y)

6 0
3 years ago
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Suppose that you have eight cards. Five are green and three are yellow. The five green cards are numbered 1, 2, 3, 4, and 5. The
Marina86 [1]

Answer:

Step-by-step explanation:

Given that you have eight cards. Five are green and three are yellow. The five green cards are numbered 1, 2, 3, 4, and 5. The three yellow cards are numbered 1, 2, and 3. The cards are well shuffled. You randomly draw one card.

G = card drawn is green

Y = card drawn is yellow

E = card drawn is even-numbered

List:

Sample space = {G1, G2, G3, G4, G5, Y1, Y2, Y3}

2) P(G) = 5/8

3) P(G/E) = P(GE)/P(E)

GE = {G2, G4}

Hence P(G/E) = 2/5

4) GE = {G2, G4}

P(GE) = 2/8 = 1/4

5) P(G or E) = P(G)+P(E)-P(GE)

= 5/8 + 3/8-2/8 = 3/5

6) No there is common element as G2 and G4

Cannot be mutually exclusive

6 0
3 years ago
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