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Bond [772]
3 years ago
5

Lisa is choosing an outfit. She has two pairs of pants: jeans and khakis, two shirts:white and red, and two pairs of shoes: boot

s and heels. How many outfits choices does Lisa have?
Mathematics
1 answer:
Brums [2.3K]3 years ago
7 0

Answer:

12

Step-by-step explanation: Hope this helps

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Addison plays 1/8 of a song in 1/2 of a minute. How many minutes will he need to play a full song/
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Answer:

4 minutes

Step-by-step explanation:

1/2 minute times 8 eights of a song = 4 minutes

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What is the number of fluid ounces in 7 cups.
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2 years ago
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A player tosses a die 6 times.If gets a number 6 Atleast two times he wins 2 dollars ,otherwise he looses 1 dollar.. Find the ex
swat32

Answer:

E(x)=-0.2101

Step-by-step explanation:

The expected value for a discrete variable is calculated as:

E(x)=x_1*p(x_1)+x_2*p(x_2)

Where x_1 and x_2 are the values that the variable can take and p(x_1) and p(x_2) are their respective probabilities.

So, a player can win 2 dollars or looses 1 dollar, it means that x_1 is equal to 2 and x_2 is equal to -1.

Then, we need to calculated the probability that the player win 2 dollars and the probability that the player loses 1 dollar.

If there are n identical and independent events with a probability p of success and a probability (1-p) of fail, the probability that a events from the n are success are equal to:

P(a)=nCa*p^a*(1-p)^{n-a}

Where nCa=\frac{n!}{a!(n-a)!}

So, in this case, n is number of times that the player tosses a die and p is the probability to get a 6. n is equal to 6 and p is equal to 1/6.

Therefore, the probability  p(x_1) that a player get at least two times number 6, is calculated as:

p(x_1)=P(x\geq2)=1-P(0)-P(1) \\\\P(0) =6C0*(1/6)^{0}*(5/6)^{6}=0.3349\\P(1)=6C1*(1/6)^{1}*(5/6)^{5}=0.4018\\\\p(x_1)=1-0.3349-0.4018\\p(x_1)=0.2633

On the other hand, the probability p(x_2) that a player don't get  at least two times number 6, is calculated as:

p(x_2)=1-p(x_1)=1-0.2633=0.7367

Finally, the expected value of the amount that the player wins is:

E(x)=x_1*p(x_1)+x_2*p(x_2)\\E(x)=2*(0.2633)+ (-1)*0.7367\\E(x)=-0.2101

It means that he can expect to loses 0.2101 dollars.

3 0
3 years ago
Read 2 more answers
Any help would be greatly appreciated
harkovskaia [24]

Answer:

<h2>the first ordered pair is (-2, -2)</h2><h2>the second ordered pair is (4,0)</h2>

Step-by-step explanation:

to find the missing values, plug in the given values into the equation:

x-3y=4

the first ordered pair:

we are given a y-value (-2), so lets plug it into the equation:

x-3*(-2)=4

now solve for the missing value:

x+6=4

x=4-6

x=-2

now plug in both x and y and check if the equation is true:

(-2)-3*(-2)=4

-2+6=4

6-2=4

4=4

the first ordered pair is (-2, -2)

the second ordered pair:

we are given a x-value (4), so lets plug it into the equation:

(4)-3y=4

now solve for the missing value:

-3y=4-4

-3y=0

y=0/-3

y=0

now plug in both x and y and check if the equation is true:

(4)-3*(0)=4

4-0=4

4=4

the second ordered pair is (4,0)

8 0
3 years ago
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