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Monica [59]
3 years ago
7

find the unit price for a 7-ounce box of cookies for $2.15. Find the answer to the nearest tenth of one cent

Mathematics
1 answer:
faltersainse [42]3 years ago
5 0
<span>2.50/18 = 0.139 or just 0.139</span>
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How many minutes are in 4.8 hours
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288 minutes

Step-by-step explanation:

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3 years ago
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Somebody please help!
Leona [35]
The answer would be 101

Steps:
2+8=10
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100+1=101
3 0
3 years ago
2 divided by 1 and 6/7
ale4655 [162]

This problem, as written, requires a bit of guessing regarding your intentions.  My interpretation is that you want to do this division:


    2

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If that's correct, here's what to do:  rewrite 1  6/7 as 13/7 (an improper fraction).

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3 years ago
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2 years ago
If it takes 6 hours for a plane to travel 720km with a tail wind and 8 hours to make the return trip with a head wind. Find the
denis-greek [22]

The speed of wind and plane are 105 kmph and 15 kmph respectively.

<u>Solution:</u>

Given, it takes 6 hours for a plane to travel 720 km with a tail wind and 8 hours to make the return trip with a head wind.  

We have to find the air speed of the plane and speed of the wind.

Now, let the speed wind be "a" and speed of aeroplane be "b"

And, we know that, distance = speed x time.

\text { Now, at tail wind } \rightarrow 720=(a+b) \times 6 \rightarrow a+b=\frac{720}{6} \rightarrow a+b=120 \rightarrow(1)

Now at head wind → 720=(a-b) \times 8 \rightarrow a-b=\frac{720}{8} \rightarrow a-b=90 \rightarrow(2)

So, solve (1) and (2) by addition

2a = 210

a = 105

substitute a value in (1) ⇒ 105 + b = 120

⇒ b = 120 – 105 ⇒ b = 15.

Here, relative speed of plane during tail wind is 120 kmph and during head wind is 90 kmph.

Hence, speed of wind and plane are 105 kmph and 15 kmph respectively.

6 0
3 years ago
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