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wariber [46]
3 years ago
6

Two input capture events occur at counts 0x1037 and 0xFF20 of the free-running counter. How many counts, in decimal have transpi

red between these two events?
A. 25,891
B. 57, 421
C. 61,161
D. 64, 551
Computers and Technology
1 answer:
Gnom [1K]3 years ago
4 0

Answer:

The correct answer is C.

Explanation:

You have to do 0xFF20 - 0x1037 but first, you need to convert the counts from hexadecimal base system to decimal base system using this formula:

N = x_{1} * 16^{0} + x_{2} * 16^{1} + x_{3} * 16^{2} + x_{4} * 16^{3} + ... + x_n 16^{n-1}, where position of the x₀ is the rightmost digit of the number.

<em>Note: </em>

  • A = 10.
  • B = 11.
  • C = 12.
  • D = 13.
  • E = 14.
  • F = 15.

0xFF20 = 15*16³+15*16²+2*16¹ = 65312

0x1037 = 1*16³+3*16¹+7*16⁰ = 4151

Result: 65312 - 4151 = 61161

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