Question

Geometry.

Answer 1

The equation of a circle with center (h, k) and radius r is

$(x - h)^{2} + (y - k)^{2} = r^{2}$

In this case, the center of the circle is (-3, 2), and the radius is 3.
You have h = -3, k = 2, r = 3

$(x- (-3))^{2} + (y - 2)^{2} = 3^{2}$

Simplifying, you get

$(x + 3)^{2} + (y - 2)^{2} = 9$