No. We claim that
and use algebra to prove the statement.
Let
. Multiply this by ten to get
. Subtract the initial equation to give
and divide by
to see that
. Substituting into the original equation gives
, proving the desired statement.
You know 1 is not a root because the sum of the coeffcients of the equation is 14, not zero.
It is fairly easy to try 3 by synthetic division (see attachment), which tells you that 3 is a root and the remaining quadratic factor is x²-3x-5. The quadratic formula tells you the roots of that factor are
... x = (-b±√(b²-4ac))/(2a) = (3±√29)/2
The appropriate choices are
... C. (3-√29)/2
... D. (3+√29)/2
... F. 3
_____
The quadratic formula tells you the solution to
... ax²+bx+c=0
is x = (-b±√(b²-4ac))/(2a)
We have a=1, b=-3, c=-5.
Answer:
I:23/48
ii 25/48
Step-by-step explanation:
30min=0.5hr
total time exercised: 11+0.5=11.5hr
Divided by total hours of a day:
11.5/24=115/240=23/48
ii:(48-23)/48
Rounded to the nearest hundredth is 0.20 to 1. Hope that helps!
It depends on H(m) what is it?
