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aliina [53]
4 years ago
5

Given sin thata = 2/5 and 0° < thata < 90°. find sin 2 thata​

Mathematics
1 answer:
Andrej [43]4 years ago
5 0

Recall the double angle identity:

\sin2\theta=2\sin\theta\cos\theta

With \theta measuring between 0º and 90º, we know \cos\theta>0. So from the Pythagorean identity, we get

\sin^2\theta+\cos^2\theta=1\implies\cos\theta=\sqrt{1-\sin^2\theta}=\dfrac{\sqrt{21}}5

Then

\sin2\theta=2\dfrac25\dfrac{\sqrt{21}}5=\dfrac{4\sqrt{21}}{25}

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