Question

What are the values of a, b and c in the quadratic equation -2x^2+4x-3=0?

Answer 1

Answer:

$a=-2\\b=4\\c=-3$

Step-by-step explanation:

In a quadratic equation in the Standard form

$ax^2+bx+c=0$

You need to remember that "a", "b" and "c" are the numerical coefficients (Where "a" is the leading coefficient and it cannot be zero: $a\neq0$).

You can observe that the given quadratic equation is written in the Standard form mentioned before. This is:

$-2x^2+4x-3=0$

Therefore, you can identify that the values of "a", "b" and "c" are the following:

$a=-2\\b=4\\c=-3$

Answer 2

Answer:

a = -2

b = 4 and

c = -3

Step-by-step explanation:

A standard form of a quadratic equation is

ax₂ + bx + c = 0, where a, b and c are coefficients

To find the value of a, b, and c

The given equation is -2x² + 4x - 3 = 0

The degree of equation is 2, therefore it is a quadratic equation.

here a = -2, b = 4 and c = -3