All categories

3 years ago

What are the values of a, b and c in the quadratic equation -2x^2+4x-3=0?

Mathematics

2 answers:

AlladinOne [14]3 years ago

4 0

Answer:

$a=-2\\b=4\\c=-3$

Step-by-step explanation:

In a quadratic equation in the Standard form

$ax^2+bx+c=0$

You need to remember that "a", "b" and "c" are the numerical coefficients (Where "a" is the leading coefficient and it cannot be zero: $a\neq0$ ).

You can observe that the given quadratic equation is written in the Standard form mentioned before. This is:

$-2x^2+4x-3=0$

Therefore, you can identify that the values of "a", "b" and "c" are the following:

$a=-2\\b=4\\c=-3$

denis-greek [22]3 years ago

3 0

Answer:

a = -2

b = 4 and

c = -3

Step-by-step explanation:

A standard form of a quadratic equation is

ax₂ + bx + c = 0, where a, b and c are coefficients

To find the value of a, b, and c

The given equation is -2x² + 4x - 3 = 0

The degree of equation is 2, therefore it is a quadratic equation.

here a = -2, b = 4 and c = -3

You might be interested in

What is the domain of f?

larisa86 [58]

Answer:

$\huge \boxed{\mathrm{A}}$

Step-by-step explanation:

The domain of a function is all possible values for the value of x.

The denominator in a rational function cannot equal to 0.

$x+2\neq 0$

Subtracting 2 from both sides.

$x\neq -2$

The domain of the function is all real numbers except -2.

7 0

3 years ago

Fwe points whats x? x+21=99?? injoy anyone wan cht

umka21 [38]

Answer:

The answer is 78

Step-by-step explanation:

99-78=21

5 0

3 years ago

Read 2 more answers

Complete the table of values

Agata [3.3K]

Both problems give you a function in the second column and the x-values. To find out the values of a through f, you need to plug in those x-values into the function and simplify!

You need to know three exponent rules to simplify these expressions:
1) The negative exponent rule says that when a base has a negative exponent, flip the base onto the other side of the fraction to make it into a positive exponent. For example, $3^{-2} =
\frac{1}{3^{2} }$ .
2) Raising a fraction to a power is the same as separately raising the numerator and denominator to that power. For example, $(\frac{3}{4}) ^{3} = \frac{ 3^{3} }{4^{3} }$ .
3) The zero exponent rule says that any number raised to zero is 1. For example, $3^{0} = 1$ .


Back to the Problem:
Problem 1
The x-values are in the left column. The title of the right column tells you that the function is $y = 4^{-x}$ . The x-values are:
1) x = 0
Plug this into $y = 4^{-x}$ to find letter a:
$y = 4^{-x}\\
y = 4^{-0}\\
y = 4^{0}\\
y = 1$

2) x = 2
Plug this into $y = 4^{-x}$ to find letter b:
$y = 4^{-x}\\ 
y = 4^{-2}\\ 
y = \frac{1}{4^{2}} \\ 
y= \frac{1}{16}$

3) x = 4
Plug this into $y = 4^{-x}$ to find letter c:
$y = 4^{-x}\\ 
y = 4^{-4}\\ 
y = \frac{1}{4^{4}} \\ 
y= \frac{1}{256}$


Problem 2
The x-values are in the left column. The title of the right column tells you that the function is $y = (\frac{2}{3})^x$ . The x-values are:
1) x = 0
Plug this into $y = (\frac{2}{3})^x$ to find letter d:
$y = (\frac{2}{3})^x\\
y = (\frac{2}{3})^0\\
y = 1$

2) x = 2
Plug this into $y = (\frac{2}{3})^x$ to find letter e:
$y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^2\\ y = \frac{2^2}{3^2}\\
y = \frac{4}{9}$

3) x = 4
Plug this into $y = (\frac{2}{3})^x$ to find letter f:
$y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^4\\ y = \frac{2^4}{3^4}\\ y = \frac{16}{81}$

-------

Answers:
a = 1
b = $\frac{1}{16}$ 
c = $\frac{1}{256}$
d = 1
e = $\frac{4}{9}$
f = $\frac{16}{81}$