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olga nikolaevna [1]
3 years ago
12

If f(5)=288.9 when r=0.05 for the function f(t)= pe^rt, then what is the approximate value of p?

Mathematics
2 answers:
8_murik_8 [283]3 years ago
7 0

Answer:225

Step-by-step explanation:

Apex

Andreas93 [3]3 years ago
5 0

The general equation is: f(t)= pe^{rt}

The given equation is: f(5)=288.9 when r = 0.05

Following the general equation, we know the following:

t=5, r = 0.05 and  pe^{rt}  = 288.9

Substituting all unknowns, we can solve for p

pe^{0.05 * 5}= 288.9

Solving for p,

p = 225

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