Question

If f(5)=288.9 when r=0.05 for the function f(t)= pe^rt, then what is the approximate value of p?

Answer 1

Answer:225

Step-by-step explanation:

Apex

Answer 2

The general equation is: f(t)= $pe^{rt}$

The given equation is: f(5)=288.9 when r = 0.05

Following the general equation, we know the following:

t=5, r = 0.05 and  $pe^{rt}$  = 288.9

Substituting all unknowns, we can solve for p

$pe^{0.05 * 5}$= 288.9

Solving for p,

p = 225